Answer:
Group 8 or Group 0
Explanation:
Group 8 or Group 0 are generally inert gases with Helium as the first member in that group. Their complete duplet (in the case of Helium) and Octet (in the case of Neon) configuration makes them very stable and chemically un-reactive.
Answer:
Check the attached one..I only draw the Dot method of Magnesium and Fluorine.. since i love chemistry ..Hope this helps you...Balance you have to do it yourself..If you didn't get the answer let me know in the comments..But you have try okay..
Answer:
Tests for unsaturation involves addition across the multiple bonds in the unsaturated compound.
Explanation:
In organic chemistry, we define an unsaturated compound as any compound that contains a double or triple bond. These multiple bonds are also known as pi bonds.
There are two major tests for unsaturation which shall both be discussed here.
The first test for unsaturation is by the use of bromine water. The unknown sample is passed through a solution of bromine water which normally appears reddish brown. The bromine water becomes decolorized due to addition of bromine across the multiple bond. This is a standard test for unsaturation.
Secondly, unsaturated compounds decoulourize a solution of potassium permanganate when passed through it. This alone can not be used as a distinctive test for unsaturation.
Propenoic acid will give a positive test to the both reagents showing that it contains multiple bonds, in this particular instance, a double bond.
C) chopping a piece or wood
Explanation
Solid barium iodate and its ionic components are in a dynamic equilibrium when dissolved in an aqueous solution. Each mole of barium iodate 
dissolves to produce one mole of barium 
ions and two moles of iodate 
ions.
Thus
![K_{\text{sp}} &= & [\text{Ba}^{2+}] \cdot [\text{IO}_3^{-}]^{2}](https://tex.z-dn.net/?f=K_%7B%5Ctext%7Bsp%7D%7D%20%26%3D%20%26%20%5B%5Ctext%7BBa%7D%5E%7B2%2B%7D%5D%20%5Ccdot%20%5B%5Ctext%7BIO%7D_3%5E%7B-%7D%5D%5E%7B2%7D)
.
Given that
of 
from the question, and
![[\text{Ba}(\text{IO}_3)_2, \; \text{dissolved}] = [\text{Ba}^{2+}] = 2 \; [\text{IO}_3^{-}]](https://tex.z-dn.net/?f=%5B%5Ctext%7BBa%7D%28%5Ctext%7BIO%7D_3%29_2%2C%20%5C%3B%20%5Ctext%7Bdissolved%7D%5D%20%3D%20%5B%5Ctext%7BBa%7D%5E%7B2%2B%7D%5D%20%3D%202%20%5C%3B%20%5B%5Ctext%7BIO%7D_3%5E%7B-%7D%5D)
as seen in the dissociation equilibrium,
![\begin{array}{lll}[\text{Ba}(\text{IO}_3)_2, \; \text{dissolved}]^{3} &=& [\text{Ba}^{2+}] \cdot [\text{IO}_3^{-}]^{2} \\ & = & K_{sp}\\&=&1.57\times 10^{-9} \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blll%7D%5B%5Ctext%7BBa%7D%28%5Ctext%7BIO%7D_3%29_2%2C%20%5C%3B%20%5Ctext%7Bdissolved%7D%5D%5E%7B3%7D%20%26%3D%26%20%5B%5Ctext%7BBa%7D%5E%7B2%2B%7D%5D%20%5Ccdot%20%5B%5Ctext%7BIO%7D_3%5E%7B-%7D%5D%5E%7B2%7D%20%5C%5C%20%26%20%3D%20%26%20K_%7Bsp%7D%5C%5C%26%3D%261.57%5Ctimes%2010%5E%7B-9%7D%20%5Cend%7Barray%7D)
![[\text{Ba}(\text{IO}_3)_2, \; \text{dissolved}] = \sqrt[3]{K_{\text{sp}}} = 1.16 \times 10^{-3} \; \text{mol}\cdot \text{dm}^{-3}](https://tex.z-dn.net/?f=%5B%5Ctext%7BBa%7D%28%5Ctext%7BIO%7D_3%29_2%2C%20%5C%3B%20%5Ctext%7Bdissolved%7D%5D%20%3D%20%5Csqrt%5B3%5D%7BK_%7B%5Ctext%7Bsp%7D%7D%7D%20%3D%201.16%20%5Ctimes%2010%5E%7B-3%7D%20%5C%3B%20%5Ctext%7Bmol%7D%5Ccdot%20%5Ctext%7Bdm%7D%5E%7B-3%7D)
of distilled water can thus dissolve up to
which corresponds to
