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QveST [7]
3 years ago
10

Which freezes faster salt water or sugar water ?

Chemistry
2 answers:
Nikitich [7]3 years ago
8 0
Sugar water freezes faster
erastova [34]3 years ago
4 0
Water will freeze the fastest........
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While both comets and asteroids are found to orbit the sun in our solar system which system which choice correctly explain how t
Alika [10]

Answer:

Comets are made of ice, dust, and rocky material. Asteroids are made of rock and metal material.

Explanation:

thats how they are different from each other

6 0
3 years ago
How many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas?
Marysya12 [62]

4 moles of water are produced

Explanation:

  • 4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
  • The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
  • The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as 5H_{2} +2O_{2} -->  4H_{2} O + H_{2}
  • This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.
4 0
3 years ago
Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ
Mademuasel [1]

Answer:

\boxed{-6.29 \times10^{5}\text{ J}}

Explanation:

Step 1. Determine the cell potential

                                                  <u>    E°/V     </u>

2×[Cr ⟶ Cr³⁺ + 3e⁻]                  0.744  V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu]             </u>   <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu  + 2Cr³⁺    1.086  V

Step 2. Calculate ΔG°

\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}

6 0
3 years ago
Calculate the pH of 1.00 L of a buffer that contains 0.105 M HNO2 and 0.170 M NaNO2. What is the pH of the same buffer after the
kari74 [83]

Answer:

1.- pH =3.61

2.-pH =3.53

Explanation:

In the first part of this problem we can compute the pH of the buffer by making use of the Henderson-Hasselbach equation,

pH = pKa + log [A⁻]/[HA]

where [A⁻] is the conjugate base anion concentration ( [NO₂⁻]), [HA] is the weak acid concentration,[HNO₂].

In the second part, our strategy has to take into account that some of the weak base NO₂⁻ will be consumed by reaction with the very strong acid HCl. Thus, first we will calculate the new concentrations, and then find the new pH similar to the first part.

First Part

pH  = 3.40+ log {0.170 /0.105}

pH =  3.61

Second Part

# mol HCl = ( 0.001 L ) x 12.0 mol / L = 0.012

# mol NaNO₂ reacted = 0.012 mol ( 1: 1 reaction)

# mol NaNO₂ initial = 0.170 mol/L x 1 L = 0.170 mol

# mol NaNO₂ remaining = (0.170 - 0.012) mol  = 0.158

# mol HNO₂ produced = 0.012 mol

# mol HNO₂ initial = 0.105

# new mol HNO₂ = (0.105 + 0.012) mol = 0.117 mol

Now we are ready to use the Henderson-Hasselbach with the new ration. Notice that we dont have to calculate the concentration (M) since we are using a ratio.

pH = 3.40 + log {0.158/.0117}

pH = 3.53

Notice there is little variation in the pH of the buffer. That is the usefulness of buffers.

4 0
2 years ago
Read 2 more answers
Is a Daisy a prokaryote or a eukaryote
goldenfox [79]
<span>A daisy is a <em>eukaryote. </em>Because since the plant is a kingdom under the domain "Eukarya".
<em>~Hope this helped! :)</em></span>
7 0
2 years ago
Read 2 more answers
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