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Anuta_ua [19.1K]
3 years ago
10

A reaction has a theoretical yield of 45.8 g. when the reaction is carried out, 37.2 g of the product forms. what is the percent

yield?
Chemistry
2 answers:
sasho [114]3 years ago
7 0
W=(m'/m)·100%

m'=37.2 g
m=48.5 g

w=(37.2/48.5)·100%=76.7%
Ganezh [65]3 years ago
6 0

Answer:

81.22 %

Explanation:

Percent yield is the ratio of the actual yield to the theoretical yield. The higher is the actual yield the higher is the percent yield. Actual yield is always less than theoretical yield.  

Given,

Theoretical yield = 45.8 g

Actual yield = 37.2 g  

Percent yield = \frac{Actual yield}{Theoretical yield }x 100

                       = \frac{37.2 g}{45.8 g }x 100 = 81.22 %

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Need to balance these equations
Brrunno [24]

The balanced chemical reaction of potassium chloride involves 2 moles of potassium to react with 1 mole of chlorine and other are explained below.

<h3>What is balanced equation?</h3>

Balanced chemical equations are those equations in which all entities are present in same amount on reactant as well as on the product side of the reaction.

Given chemical reactions are:

  • First equation is a balanced equation in which nitrogen reacts with hydrogen to form ammonia because all are present in same quantity on both sides.
  • Second equation is not a balances equation as number of chlorine atoms are not present in same quantity, so balanced equation is:

        2K + Cl₂ → 2KCl

  • Balanced equation for the third reaction is:

        CF₄ + 2Br₂ → CBr₄ + 2F₂

  • Balanced equation for the fourth reaction is:

        GaF₃ + 3Cs → 3CsF + Ga

  • Fifth reaction between barium sulfide and platinum di fluoride is balanced as all atoms are present in same amount on both sides.
  • Balanced equation for the last reaction is:

        MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF

Hence in the formation of potassium chloride balanced equation involves 2 moles of potassium to react with 1 mole of chlorine.

To know more about balanced equation, visit the below link:

brainly.com/question/26694427

#SPJ1

5 0
2 years ago
The correct number of significant figures in the following measurement is: 0.0760100 x 10^3
tester [92]

Answer:

4

Explanation:

7.60100, but we count as significant figures only the 0s b/n non-zero numbers

6 0
4 years ago
What kind of inhibitors are transition state analogs usually classified as? uncompetitive inhibitors competitive inhibitors nonc
Masteriza [31]
<h2>Competitive inhibitors.</h2>

Explanation:

▪ Transition state analogs can be used as inhibitors in enzyme-catalyzed reactions which are done by blocking the active site of the enzyme.

▪ A transition state analog is somewhat the same as that of the transition state.

▪These are better inhibitors than the substrate analogs in competitive inhibition, the reason is that they bind tighter to the enzyme rather than the substrate.

▪ Thus, they are classified as competitive inhibitors.

3 0
3 years ago
How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
levacccp [35]

Answer:

Total moles of ions are released in water are 1.131\times 10^{-5} mol.

Explanation:

Mass of calcium nitrate = 6.18\times 10^{-4} g

Molar mass of calcium nitrate = 164 g/mol

Moles of calcium nitrate = \frac{6.18\times 10^{-4} g}{164 g/mol}=3.77\times 10^{-6} mol

Ca(NO_3)_2(aq)\rightarrow Ca^{2+}(aq)+2NO_3^{-}(aq)

According to reaction, 1 mole of calcium nitrate gives 1 mole of calcium ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

1\times 3.77\times 10^{-6} mol=3.77\times 10^{-6} mol of calcium ions

According to reaction, 1 mole of calcium nitrate gives 2 mole of nitrate ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

2\times 3.77\times 10^{-6} mol=7.54\times 10^{-6} mol of nitrate ions

Total moles of ions are released :

3.77\times 10^{-6} mol+7.54\times 10^{-6} mol=11.31\times 10^{-6} mol\approx 1.131\times 10^{-5} mol

6 0
3 years ago
Please help this will determine my grade so I beg help me out and my grade
Lelu [443]

Answer:

C: checking your email

Explanation:

I believe that C would be impossible, as you cannot use wireless networks without radio waves

7 0
3 years ago
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