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Anuta_ua [19.1K]
3 years ago
10

A reaction has a theoretical yield of 45.8 g. when the reaction is carried out, 37.2 g of the product forms. what is the percent

yield?
Chemistry
2 answers:
sasho [114]3 years ago
7 0
W=(m'/m)·100%

m'=37.2 g
m=48.5 g

w=(37.2/48.5)·100%=76.7%
Ganezh [65]3 years ago
6 0

Answer:

81.22 %

Explanation:

Percent yield is the ratio of the actual yield to the theoretical yield. The higher is the actual yield the higher is the percent yield. Actual yield is always less than theoretical yield.  

Given,

Theoretical yield = 45.8 g

Actual yield = 37.2 g  

Percent yield = \frac{Actual yield}{Theoretical yield }x 100

                       = \frac{37.2 g}{45.8 g }x 100 = 81.22 %

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6 0
4 years ago
How many liters of 1.75 M solution could be made using 35 grams of NaCl?
dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
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V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
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3 years ago
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Answer:

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7 0
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