Ask question

Ask question

All categories

3 years ago

13

Farmers during the dust bowl of the 1930s watched their soil be carried away by wind what process removed the soil from the plac

e it originated to distant locations
A. Comentation
B. Erosion
C. Lithification
D. Sediments

2 answers:

creativ13 [48]3 years ago

8 0

Answer:EROSION

Explanation:

YUP

Paha777 [63]3 years ago

6 0

Answer: i’m pretty sure it’s erosion

You might be interested in

A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is

LenaWriter [7]

Answer:

0.2

Explanation:

F= BIL sin©

3= B×10×1.5 sin90

B=3/15

B= 0.2

8 0

2 years ago

Young animals often learn valuable hunting skills through

uysha [10]

They're Farther's, Genes.

7 0

3 years ago

Read 2 more answers

Technician A says the charging system recharges the battery by supplying a constant and relatively low charge to the battery. Te

brilliants [131]

Answer:

Technician B is correct

Explanation:

Charging systems works on the principle of magnetism. Charging system uses electromagnetic induction to generate electrical energy.

Electromagnetic principles states that voltage will be produced when there is a motion between conductor and the magnetic field.

5 0

3 years ago

Two very large parallel metal plates, separated by 0.20 m, are connected across a 12-V source of potential. An electron is relea

Semmy [17]

Answer:

${\rm K} = 2.4\times 10^{-19}~J$

Explanation:

The electric field inside a parallel plate capacitor is

$E = \frac{Q}{2\epsilon_0 A}$

where A is the area of one of the plates, and Q is the charge on the capacitor.

The electric force on the electron is

$F = qE = \frac{qQ}{2\epsilon_0 A}$

where q is the charge of the electron.

By definition the capacitance of the capacitor is given by

$C = \epsilon_0\frac{A}{d} = \frac{Q}{V}\\\frac{Q}{\epsilon_0 A} = \frac{V}{d} = \frac{12}{0.20} = 60$

Plugging this identity into the force equation above gives

$F = \frac{qQ}{2\epsilon_0 A} = \frac{q}{2}(\frac{Q}{\epsilon_0 A}) = \frac{q}{2}60 = 30q$

The work done by this force is equal to change in kinetic energy.

W = Fx = (30q)(0.05) = 1.5q = K

The charge of the electron is $1.6 \times 10^{-19}$

Therefore, the kinetic energy is $2.4\times 10^{-19}$

8 0

3 years ago

Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart

almond37 [142]

The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

<em>Mass of cart 1 = m1 = 1 kg</em>
<em>Mass of cart 2 = m2 = 2kg</em>
<em>Force applied on cart 1 = 2 N</em>

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

$F_1 = -F_2$

$F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N$

Thus, the force exerted on the cart 2 during the collision is 2 N.

Learn more about Newton's third law of motion here: brainly.com/question/13874955

5 0

2 years ago