Answer:
x coordinate = -1.66 m
y coordinate is = -0.825m
Explanation:
Suppose z be the distance form the first charge and z + sqrt(1^2 +.5^2) be the distance from the second So z + sqrt(1+.25) = z + 1.12
We have k*2.0x10^-6/s^2 = k*6x10^-6/(s+1.12)^2
0.0356s^2 -0.019s-0.0897=0
s=1.876m
The angle of the line between the two charges is arctan(.5/1) = 26.6o
x coordinate = -1.876*cos(26.6) = -1.66m
y coordinate is -1.876*sin(26.6) = -0.825m
When you play a piano, your energy increases in a uniform, continuous manner and is therefore quantized.When you play a piano, you can press only on individual keys, so that your energy is restricted to certain values and is therefore quantized.
To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.
From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by
Where,
Final velocity
Initial Velocity
a = Acceleration
x = Displacement
Acceleration can be expressed in terms of the drag coefficient by means of
Frictional Force
Force by Newton's second Law
Where,
m = mass
a= acceleration
Kinetic frictional coefficient
g = Gravity
Equating both equation we have that
Therefore,
Re-arrange to find x,
The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.
Answer:
u = - 38.85 m/s^-1
Explanation:
given data:
acceleration = 2.10*10^4 m/s^2
time = 1.85*10^{-3} s
final velocity = 0 m/s
from equation of motion we have following relation
v = u +at
0 = u + 2.10*10^4 *1.85*10^{-3}
0 = u + (21 *1.85)
0 = u + 38.85
u = - 38.85 m/s^-1
negative sign indicate that the ball bounce in opposite directon
