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Levart [38]
3 years ago
6

Can someone please help me

Physics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

Its the first choose

Explanation:

The excretory system is the system of an organism's body that performs the function of excretion, the bodily process of discharging wastes

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What are the steps to the scientific method
just olya [345]

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

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4 years ago
An elastic conducting material is stretched into a circular loop of 14.7 cm radius. It is placed with its plane perpendicular to
Hunter-Best [27]

Answer: 0.66 V

Explanation:

Given

Magnetic field, B = 0.963 T

Instantaneous rare = 74.5 cm/s = 0.745 m/s

radius, r = 14.7 cm = 0.147 m

We will use the formula

emf = dΦ/dt

emf = d(BA)/dt

emf = d(Bπr²)/dt

if B is constant, then we can say

emf = Bπ d(r²)/dt on differentiating, we have,

emf = Bπ (2r dr/dt)

emf = 2πrB dr/dt substituting each values, we have

emf = 2 * 3.142 * 0.147 * 0.963 * 0.745

emf = 0.66 V

Therefore, the induced emf in the loop at that instant is 0.66 V

3 0
3 years ago
The metal cover that seals the top of the cylinder
padilas [110]

Answer:a lid

Explanation bob pulled the lid off the jar of pickles

5 0
3 years ago
Read 2 more answers
It takes 50.0 J to push a large box 4.00 m across a floor. Assuming the push is in the same direction as the move, what is the m
Blababa [14]
<h3><u>Answer;</u></h3>

12.5 Newtons

<h3><u>Explanation;</u></h3>

Work done is defined as the product of force and distance covered or moved. It is measured in joules.

Work done = Force × distance

Therefore; making force the subject;

Force = work done/distance

         = 50.0 J/ 4.00 m

         =<u> 12.5 Newtons.</u>

8 0
3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
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