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maw [93]
3 years ago
13

O que acontece quando uma moeda escurece? (oxidos quimica )

Chemistry
1 answer:
True [87]3 years ago
8 0

Answer:

As moedas ficam sujas devido ao oxigênio do ar reagindo com o metal para formar óxido de cobre. Eles se tornam mais escuros à medida que envelhecem, à medida que a camada de óxido aumenta. O vinagre é um ácido (ácido acético) que pode ser usado para limpar superfícies e remover os óxidos indesejados.

Explanation:

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Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord
OleMash [197]

Answer:

0.0626 M

Explanation:

Equation of the reaction

CH3COOH(aq) + NaOH(aq) ---------> CH3COONa(aq) + H2O

Concentration of acid CA= ???

Concentration of base CB= 0.1943 M

Volume of acid VA= 10.0ml

Volume of base VB= 32.22 ml

Number of moles of acid NA= 1

Number of moles of base NB= 1

From

CA= CB VB NA/VA NB

Hence ;

CA= 0.1943 M × 32.22 ml × 1/10.0ml ×1

CA= 0.0626 M

3 0
4 years ago
Why does argon exist in nature as individual argon atoms and chlorine exist in nature as 2 chlorine atoms covalently bonded toge
Katarina [22]

Answer:

Argon has 8 valence electrons and no extras, it does not require a bond in order to fill its shells, its satisfied by itself.

Chlorine is missing 1 Electron, if it connects with another Chlorine it will be satisfying both of their needs with a Covalent bond.

Explanation:

8 0
3 years ago
The first four electrons shells fill out in what electron configuration?
Sidana [21]

Explanation:

2, 8, 8, 2 is the electron arrangement of Calcium.

The way that the "orbitals", the shells, fill up is given as

1s^{2}  2s^{2}  2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} . . . etc etc.

It is more stable for the fourth shell to start filling up with an electron pair, and then subsequent electrons filling up the third shell again.

So while potassium 19, is 2,8,8,1

And calcium 20, is 2,8,8,2

Scandium 21 will fill up as, 2,8,9,2

This will continue until we reach Zinc 30, which will fill up as 2,8,18,2. The third shell is now "full", and the fourth shell will now being to fill up.

The fourth orbital starts getting filled up again, Gallium 31, is 2,8,18,3

3 0
2 years ago
PLEASE HELP
PIT_PIT [208]

Do you go to Millbrook? 23.9kPa

7 0
3 years ago
N204(0) + 2NO2(g)
user100 [1]

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

<h3>Further explanation</h3>

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}

Setup 1 :

\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}

Q<K⇒The reaction moved to the right (products)

Setup 2 :

\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}

Q=K⇒the system at equilibrium

Setup 3 :

\tt Q=\dfrac{0.230^2}{0.420}=0.126

Q>K⇒The reaction moved to the left (reactants)

8 0
3 years ago
Read 2 more answers
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