Answer:
The force that keeps the planets in orbit is gravity.
The least net force applied : Car 3(12 N)
<h3>Further explanation </h3>
Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object
∑F = m. a
Car 1 ⇒m=0.5 kg, a=36 m/s²
Car 2⇒m=0.8 kg, a=50 m/s²
Car 3⇒m=0.6, a=20 m/s²
Car 4⇒m=1, a=19~m/s²
Answer: This is from a wiki i found. Approximately one third of a cell’s proteins are destined to function outside the cell’s boundaries or while embedded within cellular membranes. Ensuring these proteins reach their diverse final destinations with temporal and spatial accuracy is essential for cellular physiology. In eukaryotes, a set of interconnected organelles form the secretory pathway, which encompasses the terrain that these proteins must navigate on their journey from their site of synthesis on the ribosome to their final destinations. Traffic of proteins within the secretory pathway is directed by cargo-bearing vesicles that transport proteins from one compartment to another. Key steps in vesicle-mediated trafficking include recruitment of specific cargo proteins, which must collect locally where a vesicle forms, and release of an appropriate cargo-containing vessel from the donor organelle (Figure 1). The newly formed vesicle can passively diffuse across the cytoplasm, or can catch a ride on the cytoskeleton to travel directionally. Once the vesicle arrives at its precise destination, the membrane of the carrier merges with the destination membrane to deliver its cargo. Have a nice day.
Explanation: Plz make brainliest
Answer: The atomic weight of the metal would be 85.47.
Explanation:
Mass of isotope 1 of metal = 84.9118
% abundance of isotope 1 of metal = 72.15% = 
Mass of isotope 2 of metal= 86.9092
% abundance of isotope 2 of metal = 27.85% = 
Formula used for average atomic mass of an element :
![A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2884.9118%29%5Ctimes%20%5Cfrac%7B72.15%7D%7B100%7D%29%2B%2886.9092%29%5Ctimes%20%5Cfrac%7B27.85%7D%7B100%7D%5D%5D)
Therefore, the atomic weight of the metal would be 85.47.
