Question

A 1000-kilogram truck accelerates uniformly from rest, reaching a speed of 50 meters per second in 10 seconds. During the 10 seconds, the truck has traveled a distance of

Answer 1

Answer:

250 m

Explanation:

1. First, we have to calculate the acceleration:

$\boxed{\mathsf{v=v_o+a\cdot t}}$

where:

v = present velocity

vo = initial velocity

a = acceleration

t = time

2. Let us use given information and substitute in the expression above. Hence:

$\mathsf{50=0+a\cdot10}\\\\\mathsf{50=10\cdot a}\\\\\mathsf{a=\dfrac{50}{10}}\\\\\therefore \boxed{\mathsf{a=5\,m/s^2}}}$

3. Now we can calculate traveled distance with Torricelli's equation:

$\boxed{\mathsf{v^2=v_o^2+2\cdot a \cdot d}}$

where:

v = present velocity

vo = initial velocity

a = accelerarion

d = distance

4. So, we get:

$\mathsf{50^2=0^2+2\cdot 5 \cdot d}\\\\\mathsf{2500=10\cdot d}\\\\\mathsf{d=\dfrac{2500}{10}}\\\\\therefore \boxed{\mathsf{d=250\,m}}$

Conclusion: during 10 seconds the truck has traveled a distance of 250 m.

Have a nice day! : )