Answer:
100m
Explanation:
100m
s=ut+1/2at^2
s= unknown, u=0, a=2, t=10
s=0*10+1/2(2)(10)^2
s=1/2(2)(100)
s=1(100)
displacement = 100 meters
Answer:
Coefficient of friction is 
.
Work done is 
.
Explanation:
Given:
Mass of the box (
): 
kg
Force needed (
): 
N
The formula to calculate the coefficient of friction between the floor and the box is given by
Here, 
is the coefficient of friction and 
is the acceleration due to gravity.
Substitute N for , kg for and 
m/s² for into equation (1) and solve to calculate the value of the coefficient of friction.
The formula to calculate the work done in overcoming the friction is given by
Here, 
is the work done and 
is the distance travelled.
Substitute N for and 
for into equation (2) to calculate the work done.
Recall that in the equilibrium position, the upward force of the spring balances the force of gravity on the weight is given below.
Explanation:
Measure unstretched length of spring, L. E.g. L = 0.60m.
Set mass to a convenient value (e.g. m = 0.5kg).
Hang mass.
Measure new spring length, L'. E.g. L' = 0.70m.
Calculate extension: e = L' - L = 0.70 – 0.60 = 0.10m
Use mg = ke (in equilibrium weight = tension)
k = mg/e
Don't know what value you are using for example. Suppose it is 10N/kg (same thing as 10m/s²).
k = 0.5*10/0.10 = 50 N/m
Repeat for a few different masses. (L always stays the same.)
Take the average of your k values.
A. Their displacement is the same, zero miles.
