The most common metals used for permanent magnets are iron, nickel, cobalt and some alloys of rare earth metals
Vf = Final velocity.
Vi = initial velocity
a = acceleration.
t = time
Vf = Vi + at
Vf = 0 + (2 m/s^2)(3s)
Vf = 6 m/s south
Explanation:
We want to find the statement that is proven by the fact that the balls reach the same height.
A isn't supported by the evidence. Balls can reach the same height without having the same initial speed.
B isn't supported by the evidence. Balls can reach the same height without having the same launch angle.
C is supported. Projectiles spend the same amount of time going up as they do coming down, so if two projectiles reach the same height, then they must spend the same amount of time in the air.
D isn't supported by the evidence. Balls thrown at the same speed and complementary angles have the same range but different heights.
E isn't supported by the evidence. The mass of the ball doesn't affect the height.
Answer:
Acceleration, a = 2.38m/s²
Explanation:
Given the following data;
Mass = 1.01 kg
Force = 2.4N
To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
- m represents the mass of an object.
- a represents acceleration.
Making acceleration (a) the subject, we have;
Substituting into the equation, we have;
<em>Acceleration, a = 2.38m/s²</em>
<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>
If we have to figure air resistance into it, then we don't have enough information to find an answer.
If the air around it is going to have an effect on how it falls, then it'll depend on the thickness of the book, the shape of the book, whether it's a hard-cover or soft-cover, how far the covers stick out past the pages, how smooth or rough the covers are, how bumpy the binding it. and what position you hold it in before you let it go.
(THAT's why we always ignore air resistance, especially when the question is actually about gravity anyway.)