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wolverine [178]
3 years ago
10

Sources of error in a diverging lens experiment ​

Physics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

Lens and the virtual image was the image distance. Error was made when measuring the distances and determining values that were reasonable for focal length, so this error was accounted for when calculating the focal length by adding or subtracting uncertainties from the values.Plane mirrors, convex mirrors, and diverging lenses can never produce a real image. A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). 5.

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I believe it is, since the heat causes the water to evaporate and cause condensation,
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A marble on a frictionless track, starting from point A in the drawing, is projected down the curved runway. (This means that th
EleoNora [17]

Answer:

v = 4.4 m / s

Explanation:

Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.

Starting point. Point A

          Em₀ = K + U = ½ m v2 + mg y_a

point B.

          Em_f = U = m g y

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        ½ m v² = m g (y -y_a)

         v = \sqrt {2g ( y - y_a)}

         In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m

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4 0
3 years ago
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
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Answer:

(B) 1.6 m/s^2

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The equation of the forces acting on the box in the direction parallel to the slope is:

mg sin \theta - \mu N = ma (1)

where

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\mu N is the frictional force, with \mu = 0.6 being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

N-mg cos \theta =0

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N=mg cos \theta

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a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2

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