I believe it is, since the heat causes the water to evaporate and cause condensation,
Answer:
v = 4.4 m / s
Explanation:
Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.
Starting point. Point A
Em₀ = K + U = ½ m v2 + mg y_a
point B.
Em_f = U = m g y
the energy is conserved
Em₀ = Em_f
½ m v² + mg y_a = m g y
½ m v² = m g (y -y_a)
v =
In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m
v =
v = 4.4 m / s
Answer:
(B) 1.6 m/s^2
Explanation:
The equation of the forces acting on the box in the direction parallel to the slope is:
(1)
where
is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity,
being the angle of the incline
is the frictional force, with
being the coefficient of kinetic friction, N being the normal reaction of the plane
a is the acceleration
The equation of the force along the direction perpendicular to the slope is

where
is the component of the weight in the direction perpendicular to the slope. Solving for N,

Substituting into (1), solving for a, we find the acceleration:

<span>.Ask a Question
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.Construct a Hypothesis.
.Test Your Hypothesis by Doing an Experiment
.Analyze Your Data and Draw a Conclusion.
<span>.Communicate Your Results.</span></span>