The <em>estimated</em> displacement of the center of mass of the olive is ![\overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m]](https://tex.z-dn.net/?f=%5Coverrightarrow%7B%5CDelta%20r%7D%20%3D%20-0.046%5C%2C%5Chat%7Bi%7D%20-0.267%5C%2C%5Chat%7Bj%7D%5C%2C%5Bm%5D)
.
<h3>Procedure - Estimation of the displacement of the center of mass of the olive</h3>
In this question we should apply the definition of center of mass and difference between the coordinates for <em>dynamic</em> (
) and <em>static</em> conditions (
) to estimate the displacement of the center of mass of the olive (
):
![\vec r - \vec r_{o} = \left[\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot(m_{i}\cdot g + F_{i, x})}{\Sigma \limits_{i =1}^{2}(F_{i,x}+m_{i}\cdot g)} ,\frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot(m_{i}\cdot g + F_{i, y})}{\Sigma \limits_{i =1}^{2}(F_{i,y}+m_{i}\cdot g)} \right]-\left(\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}, \frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}\right)](https://tex.z-dn.net/?f=%5Cvec%20r%20-%20%5Cvec%20r_%7Bo%7D%20%3D%20%5Cleft%5B%5Cfrac%7B%5CSigma%5Climits_%7Bi%3D1%7D%5E%7B2%7Dr_%7Bi%2Cx%7D%5Ccdot%28m_%7Bi%7D%5Ccdot%20g%20%2B%20F_%7Bi%2C%20x%7D%29%7D%7B%5CSigma%20%5Climits_%7Bi%20%3D1%7D%5E%7B2%7D%28F_%7Bi%2Cx%7D%2Bm_%7Bi%7D%5Ccdot%20g%29%7D%20%2C%5Cfrac%7B%5CSigma%5Climits_%7Bi%3D1%7D%5E%7B2%7Dr_%7Bi%2Cy%7D%5Ccdot%28m_%7Bi%7D%5Ccdot%20g%20%2B%20F_%7Bi%2C%20y%7D%29%7D%7B%5CSigma%20%5Climits_%7Bi%20%3D1%7D%5E%7B2%7D%28F_%7Bi%2Cy%7D%2Bm_%7Bi%7D%5Ccdot%20g%29%7D%20%5Cright%5D-%5Cleft%28%5Cfrac%7B%5CSigma%5Climits_%7Bi%3D1%7D%5E%7B2%7Dr_%7Bi%2Cx%7D%5Ccdot%20m_%7Bi%7D%5Ccdot%20g%7D%7B%5CSigma%20%5Climits_%7Bi%3D%201%7D%5E%7B2%7D%20m_%7Bi%7D%5Ccdot%20g%7D%2C%20%5Cfrac%7B%5CSigma%5Climits_%7Bi%3D1%7D%5E%7B2%7Dr_%7Bi%2Cy%7D%5Ccdot%20m_%7Bi%7D%5Ccdot%20g%7D%7B%5CSigma%20%5Climits_%7Bi%3D%201%7D%5E%7B2%7D%20m_%7Bi%7D%5Ccdot%20g%7D%5Cright%29)
(1)
Where:
- x-Coordinate of the i-th element of the system, in meters.
- y-Coordinate of the i-th element of the system, in meters. 
- x-Component of the net force applied on the i-th element, in newtons.
- y-Component of the net force applied on the i-th element, in newtons. 
- Mass of the i-th element, in kilograms.
- Gravitational acceleration, in meters per square second.
If we know that ![\vec r_{1} = (0, 0)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7B1%7D%20%3D%20%280%2C%200%29%5C%2C%5Bm%5D)
, ![\vec r_{2} = (1, 2)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7B2%7D%20%3D%20%281%2C%202%29%5C%2C%5Bm%5D)
, ![\vec F_{1} = (0, 3)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B1%7D%20%3D%20%280%2C%203%29%5C%2C%5BN%5D)
, ![\vec F_{2} = (-3, -2)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B2%7D%20%3D%20%28-3%2C%20-2%29%5C%2C%5BN%5D)
, 
, 
and 
, then the displacement of the center of mass of the olive is:
<h3>Dynamic condition
![\vec{r} = \left[\frac{(0)\cdot (0.50)\cdot (9.807)+(0)\cdot (0) + (1)\cdot (1.50)\cdot (9.807) + (1)\cdot (-3)}{(0.50)\cdot (9.807) + 0 + (1.50)\cdot (9.807)+(-3)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (0)\cdot (3) + (2)\cdot (1.50)\cdot (9.807) +(2) \cdot (-2)}{(0.50)\cdot (9.807) + (3)+(1.50)\cdot (9.807)+(-2)} \right]](https://tex.z-dn.net/?f=%5Cvec%7Br%7D%20%3D%20%5Cleft%5B%5Cfrac%7B%280%29%5Ccdot%20%280.50%29%5Ccdot%20%289.807%29%2B%280%29%5Ccdot%20%280%29%20%2B%20%281%29%5Ccdot%20%281.50%29%5Ccdot%20%289.807%29%20%2B%20%281%29%5Ccdot%20%28-3%29%7D%7B%280.50%29%5Ccdot%20%289.807%29%20%2B%200%20%2B%20%281.50%29%5Ccdot%20%289.807%29%2B%28-3%29%7D%2C%20%5Cfrac%7B%280%29%5Ccdot%20%280.50%29%5Ccdot%20%289.807%29%20%2B%20%280%29%5Ccdot%20%283%29%20%2B%20%282%29%5Ccdot%20%281.50%29%5Ccdot%20%289.807%29%20%2B%282%29%20%5Ccdot%20%28-2%29%7D%7B%280.50%29%5Ccdot%20%289.807%29%20%2B%20%283%29%2B%281.50%29%5Ccdot%20%289.807%29%2B%28-2%29%7D%20%20%5Cright%5D)
![\vec r = (0,704, 1.233)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r%20%3D%20%280%2C704%2C%201.233%29%5C%2C%5Bm%5D)
</h3>
<h3>Static condition</h3><h3>
![\vec{r}_{o} = \left[\frac{(0)\cdot (0.50)\cdot (9.807) + (1)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807) + (1.50)\cdot (9.807)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (2)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807)+(1.50)\cdot (9.807)} \right]](https://tex.z-dn.net/?f=%5Cvec%7Br%7D_%7Bo%7D%20%3D%20%5Cleft%5B%5Cfrac%7B%280%29%5Ccdot%20%280.50%29%5Ccdot%20%289.807%29%20%2B%20%281%29%5Ccdot%20%281.50%29%5Ccdot%20%289.807%29%7D%7B%280.50%29%5Ccdot%20%289.807%29%20%2B%20%281.50%29%5Ccdot%20%289.807%29%7D%2C%20%5Cfrac%7B%280%29%5Ccdot%20%280.50%29%5Ccdot%20%289.807%29%20%2B%20%282%29%5Ccdot%20%281.50%29%5Ccdot%20%289.807%29%7D%7B%280.50%29%5Ccdot%20%289.807%29%2B%281.50%29%5Ccdot%20%289.807%29%7D%20%20%5Cright%5D)
</h3><h3>
![\vec r_{o} = \left(0.75, 1.50)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7Bo%7D%20%3D%20%5Cleft%280.75%2C%201.50%29%5C%2C%5Bm%5D)
</h3><h3 /><h3>Displacement of the center of mass of the olive</h3>
![\overrightarrow{\Delta r} = (0.704-0.75, 1.233-1.50)\,[m]](https://tex.z-dn.net/?f=%5Coverrightarrow%7B%5CDelta%20r%7D%20%3D%20%280.704-0.75%2C%201.233-1.50%29%5C%2C%5Bm%5D)
![\overrightarrow{\Delta r} = (-0.046, -0.267)\,[m]](https://tex.z-dn.net/?f=%5Coverrightarrow%7B%5CDelta%20r%7D%20%3D%20%28-0.046%2C%20-0.267%29%5C%2C%5Bm%5D)
The <em>estimated</em> displacement of the center of mass of the olive is . 
To learn more on center of mass, we kindly invite to check this verified question: brainly.com/question/8662931
Answer:
Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height
Explanation:
As we know that initially ball is held at height h = 40 cm
So here we can say that kinetic energy of the ball is zero and potential energy is given as
now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies
So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height
While if we assume that there is no energy loss during collision then in that case ball will reach to same height again
Two teams of five trying to shoot in the hoop, the ball is moving around the court by players drippling or passing, the team with the basketball is called offense
<span>a. A solid will gain kinetic energy and become a liquid.</span>
Answer:
Explanation:
3. The word circuit means "go around", therefore a circuit is a pathway or closed path around which electricity (or water) flows.
4. Electrons flowing through a wire can be compared to water flowing through a hose. Once the flow of electrons or water is going, work, is performed.
5. You would get shocked in a bumper car by touching the floor and the ceiling at the same time. This means you are completing the circuit allowing electricity to flow.
6. Electricity from a wall outlet has enough energy to stop your
heart.
7. Electricity is the flow of electrons, because electrons move or jump from atom to atom.
8. Materials that allow electrons to move easily from atom to atom are called conductors.
9. Materials that do not allow electrons to flow easily are called insulators.
10. Semi- conductors are materials that are somewhere in between
.
11. Voltage is the force or pressure of electricity and is compared to the amount of water pressure in a hose.
12. Current (amps
) is the amount of electricity and is compared to the amount of water in a hose
.
13. Watts (power) is the term for work performed by electricity.
