All categories

3 years ago

What does it mean when there is a curved line going upwards on a graph?science 8th grade :)

Physics

1 answer:

yulyashka [42]3 years ago

8 0

Answer: it is the asymptote

Explanation: a line that continually approaches a given curve but does not meet it at any finite distance.

You might be interested in

A small circular coil of 5 turns of wire lies in a uniform magnetic field of 0.8 T, so that the normal to the plane of the coil

Travka [436]

Complete question:

A small circular coil of 5 turns of wire lies in a uniform magnetic field of 0.8 T, so that the normal to the plane of the coil makes an angle of 100◦ with the direction of B~ . The radius of the coil is 4 cm, and it carries a current of 1 A.

What is magnitude of the magnetic moment of the coil? Answer in units of A · m2.

Answer:

The magnetic moment of the coil is 0.0252 A.m²

Explanation:

Given;

radius of the coil, r = 4 cm = 0.04 m

number of turns of the coil, N = 5 turns

magnetic field strength B = 0.8 T

current in the coil, I = 1 A

Area of the coil, A = πr² = π(0.04)² = 0.00503 m²

magnetic moment of the coil, μ = NIA

where;

N is the number of turns

I is the current in the coil

A is the area of the coil

magnetic moment of the coil, μ = 5 x 1 x 0.00503 = 0.0252 A.m²

Therefore, the magnetic moment of the coil is 0.0252 A.m²

8 0

3 years ago

An object with a mass of 10 kg is rolled down a frictionless ramp from a height of 3 meters. If a factory worker at the bottom o

ruslelena [56]

Answer:

The amount of work the factory worker must to stop the rolling ramp is 294 joules

Explanation:

The object rolling down the frictionless ramp has the following parameters;

The mass of the object = 10 kg

The height from which the object is rolled = 3 meters

The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp

Where;

The potential energy P.E. = m × g × h

m = The mass of the ramp = 10 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the object rolls down = 3 m

Therefore, we have;

P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules

The work done by the factory worker to stop the rolling ramp = P.E. = 294 joules

8 0

2 years ago

Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th

irinina [24]

I'm not quite sure what happens to Fay so I didn't finish but hope it helps

5 0

3 years ago

Read 2 more answers

which of the following is not a type of cosmic radiation? gamma-rays, x-rays, sound waves, or cosmic rays

Archy [21]

Answer: sound waves or cosmic rays

Explanation:

Cosmic radiation consist of high energy particles,x-rays and gamma rays produce in space

7 0

3 years ago

A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at

BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

$p_{i} = p_{f}$

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}$

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

$v_{1_{i}}$ : is the initial speed of the car = 40 km/h = 11.11 m/s

$v_{2_{i}}$ : is the initial speed of the lorry = 20 km/h = 5.56 m/s

$v_{1_{f}}$ : is the final speed of the car =?

$v_{2_{f}}$ : is the final speed of the lorry =?

Since the two vehicles become tightly locked together after the collision $v_{1_{f}}$ = $v_{2_{f}}$ :

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})$

$v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s$

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!

8 0

2 years ago