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3 years ago

What does it mean when there is a curved line going upwards on a graph?science 8th grade :)

Physics

1 answer:

yulyashka [42]3 years ago

8 0

Answer: it is the asymptote

Explanation: a line that continually approaches a given curve but does not meet it at any finite distance.

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Three astronauts outside a spaceship and that they decide to play catch. All the astronauts weigh the same on Earth and are equa

guajiro [1.7K]

Answer:

Well concluding there is no gravity their motions would be slow and lightweighted. Let's say they were playing on Earth it would approximately take around 5 to 6 minutes even less, so in space it will approximately take around 10 to 12 minutes may be more but this is just my opinion after using my calculator! Hope this helped!

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3 years ago

On her camping trip, Penelope was in charge of collecting firewood. The firewood she found had a mass of 120 g and a volume of 4

zloy xaker [14]

From the formula: density=mass/volume
But first, we have to convert the cm³ to m³ by multiplying the value in cm³ by 10^-6, by so doing we'll have the volume to be 0.48*10^-3cm³.
we will also need to convert the mass which is in g to kg by simply dividing by 1000 so the mass becomes 0.12kg
Now we can solve for the density using the formula I earlier stated which is the mass divided by the volume =0.12/0.48*10^-3 so the density will be 0.25*10^3kgm-3 or 2.5*10^2kgm-3

3 0

3 years ago

The mass of a hypothetical planet is 1/100 that of Earth and its radius is 1/4 that of Earth. If a person weighs 600 N on Earth,

omeli [17]

To solve this problem we will apply the Newtonian concept of gravitational acceleration produced by a planet. This relationship is given by:

$g = \frac{GM}{r^2}$

Where,

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius

The values given are based on the constants of the earth, so they can be expressed as

$M_p = \frac{1}{100} M_e$

$r_p = \frac{1}{4} r_e$

The relationship of gravity would then be given:

$g_e = \frac{GM_e}{r_e^2}$

The relationship with the new planet, from the gravity of the earth would be given

$g_p = \frac{GM_p}{r_p^2}$

$g_p = \frac{G(1/100)M_e}{(1/4 r_e)^2}$

$g_p = \frac{GM_e 16}{100 r_e^2}$

$g_p = 0.16 \frac{GM_e}{r_e^2}$

$g_p = 0.16g_e$

The relationship with the weight of the earth would be given as:

$W_e = m*g_e = 600N$

$W_p = m*g_p = m(0.16g_p)$

$W_p = (m*g_p)(0.16)$

$W_p = 600*0.16$

$W_p = 96N$

Therefore the weigh on this planet would be 96N

3 0

3 years ago

A mass M suspended by a spring with force constant k has aperiod T when set into oscillations on Earth. Its period on Mars,whose

olchik [2.2K]

Answer:

C)T

Explanation:

The period of a mass-spring system is:

$T=2\pi\sqrt\frac{m}{k}$

As can be seen, the period of this simple harmonic motion, does not depend at all on the gravitational acceleration (g), neither the mass nor the spring constant depends on this value.

6 0

4 years ago

The newton is a unit of

lutik1710 [3]

Force, the newton is a unit of force.

4 0

3 years ago

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