Answer:
The maximum electric field strength is 0.0144 V/m.
Explanation:
Given that,
Electric potential created in the heart, V = 3.6 mV
Distance, d= 0.25 m
Frequency of the the electromagnetic wave, f = 1 Hz
We need to find the maximum electric field strength created. We know that the electric potential is given by :
E is the maximum electric field strength
So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.
Inertia is the property of all matter by which it tends to remain
in constant, uniform motion unless acted on by external force.
Answer:
120 mph
Explanation:
Given:
Δx = 0.25 mi
v₀ = 0 mi/s
t = 15 s
Find: v
Δx = ½ (v + v₀) t
0.25 mi = ½ (v + 0 mi/s) (15 s)
v = 0.0333 mi/s
v = 120 mi/h
Answer:
3.16X10∧-11 m
Explanation:
1/2 mv2 = qV (KE = Electric potential energy)
velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)
2.3X10∧7m/s
now use De Broglie equation
λ = h/mv
= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)
3.16 X 10∧-11 m
or
use the above equations and substitute to get the final eqiation
λ = h/√(2mqV) = 3.16X 10∧-11 m
