Answer:
The width of the slit is 0.4 mm (0.00040 m).
Explanation:
From the Young's interference expression, we have;
(λ ÷ d) = (Δy ÷ D)
where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.
Thus,
d = (Dλ) ÷ Δy
D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 ×
m)
d = (3.30 × 563 ×
) ÷ (0.0047)
= 1.8579 ×
÷ 0.0047
= 0.0003951 m
d = 0.00040 m
The width of the slit is 0.4 mm (0.00040 m).
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
![W=K_f - K_i](https://tex.z-dn.net/?f=W%3DK_f%20-%20K_i)
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:
![K_f = 0](https://tex.z-dn.net/?f=K_f%20%3D%200)
, so the work done by the brakes to stop the bus is
![W=-K_i = -500000 J](https://tex.z-dn.net/?f=W%3D-K_i%20%3D%20-500000%20J)
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
Choice - B is the correct one.
At the top of the arc, at one end of the swing:
-- it's not going to get any higher, so the potential energy is maximum
-- it stops moving for an instant, so the kinetic energy is zero
At the bottom of the arc, in the center of the swing:
-- it's not going to get any lower, so the potential energy is minimum
-- it's not going to move any faster, so the kinetic energy is maximum
El núcleo tiene 3 protones (lo que le da al núcleo una carga de +3, identificándolo como el elemento Litio) y 4 neutrones (lo que le da un número total de masa de 7).
If it takes 1 year for this crab to travel 5,70km
Then, it will takes approximatly 1000/5,70 = 175 years to travel 1000 km