Calculate the wavelength associated with electrons moving with p.d of 1500v
1 answer:
Answer:
3.16X10∧-11 m
Explanation:
1/2 mv2 = qV (KE = Electric potential energy)
velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)
2.3X10∧7m/s
now use De Broglie equation
λ = h/mv
= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)
3.16 X 10∧-11 m
or
use the above equations and substitute to get the final eqiation
λ = h/√(2mqV) = 3.16X 10∧-11 m
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