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Margarita [4]
3 years ago
13

At which of the following temperatures does all molecular motion stop

Chemistry
1 answer:
Kamila [148]3 years ago
3 0
All molecular motion stop at 0 k wich is zero kelvin. At absolute 0 it stops. The temperature of 0 entropy at which all molecular motion stops equals in centigrades to -273.15° C which is the same as 0 in kelvin degrees. Have in mind that t<span>emperature is a measure of the average kinetic energy of the </span>molecules<span> in a material.</span>
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1 Balance each equation. Paragraph Styles Voice Sensity 2) Indicate the type of reaction by classifying each reaction as single
nika2105 [10]

1. Double replacement (DR)

2. Decomposition (D)

<h3>Further explanation</h3>

1. Al2(SO4)3 + Ca3(PO4)2 -> 2AIPO4 + 3CaSO4

Double replacement (DR) : there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

General form :

AB + CD -> AD + CB

2.  2NaCIO3 → 2NaCl + 3O2

Decomposition (D) : Reactant breakdown into simpler ones(reverse of combination)

General form :

AB ---> A + B

6 0
3 years ago
An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?
AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

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P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

P_2=666.2mmHg

Therefore, the final pressure will be, 666.2 mmHg

6 0
2 years ago
How many molecules units are in 4.5 moles of CF4
kobusy [5.1K]
1.0 mole ---------- 6.02x10²³ molecules
4.5 moles -------- ?

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= 2.709x10²⁴ molecules units
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Electromagnetic energy would be your answer :)
6 0
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