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Oxana [17]
3 years ago
10

ANSWER QUICK I VOTE AS BRAINLIEST

Chemistry
1 answer:
77julia77 [94]3 years ago
5 0
The relative humidity of the air is the ratio of the actual amount of moisture in the air to the fully saturated amount. There for the answer is 33.1% or 3.3g/kg
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If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?
Nimfa-mama [501]

Answer:

11.6 mol O₂

Explanation:

  • C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O

In order to solve this problem we need to <u>convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂)</u>. To do so we'll use a conversion factor containing the <em>stoichiometric coefficients</em> of the balanced reaction:

  • 7.4 mol CO₂ * \frac{11molO_2}{7molCO_2} = 11.6 mol O₂
4 0
2 years ago
How is earths moon different from the moons of other planets
Sedaia [141]
The earths moon is most like going to differ in size or even color
6 0
3 years ago
Read 2 more answers
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
What happens to the reaction c2h6 + 137 kj c2h4+h2 when the temperature of the reaction is increased?
Softa [21]
Answer is: at higher temperatures reaction will go to the right (forward), more products (C₂H₄ and H₂) will be produce, because this is endothermic reaction (ΔH<span> is positive, </span>energy is consumed) and according Le Chatelier's principle <span>heat is included as a reactant. </span> .
4 0
3 years ago
Which statement is always true about conversation of matter?
Firlakuza [10]

Answer:

The mass of a system does not change during a chemical reaction

Explanation:

Correct Answers

8 0
2 years ago
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