Focus your attention to the units of the given data and the unit of the final measurement you're going to solve. Through dimensional analysis,you know that the working equation would be:
Food Value = CcalΔT/m
Food value = (6.15 kJ/°C)(1.29 °C)/0.611 g = 12.98 kJ/g
Convert kJ to cal (1 kJ = 239 cal)
Food value = 12.98*239 =<em> 3,103.28 cal/g</em>
Answer:
-255.4 kJ
Explanation:
The free energy of a reversible reaction can be calculated by:
ΔG = (ΔG° + RTlnQ)*n
Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.
C₂H₂(g) + 2H₂(g) ⇄ C₂H₆(g)
Q = pC₂H₆/[pC₂H₂ * (pH₂)²]
Q = 0.261/[8.58*(3.06)²]
Q = 3.2487x10⁻³
ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)
ΔG = -255.4 kJ
To look for the value of the equilibrium constant for the cell where n=1, it is computed by:
Eo = RT / nF * ln(K)
(Eo * nF) /RT = ln(K)
(0.135 * 1mol* e- * 9.65E4C/mol*e) / (8.314J / molK * 298K) = ln(K)
10.52 = lnK
e^10.52 = e ^ lnK
K = e ^263/25
K = 37049.12 is the answer.
Answer:
the ratio of the universe's helium to hydrogen by mass is 2:5 approximately.
Explanation:
To solve this question, we assign arbitrary values to these elements in tandem to the data given in the question.
nH, Number of Hydrogen atoms = X = 100
nHe, Number of Helium atoms = 0.1X = Y = 10
From the data given, by mass:
if the mass of Hydrogen atom = 1g = 100g
therefore, the mass of a Helium atom = 4g (1*4) = 40g
Mass ratio of Helium to Hydrogen = 40:100 = 4:10 = 2:5 approximately
Answer:
sodium has got ionic bonds that are weak
compared to hydrogen covalent bonds that are strong
