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wel
3 years ago
14

What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 c

m from the other) is 413 V?
Physics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

   = 413V / 0.0795 m

    = 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

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Given below the arrangement of loading on the larger boat by two tug boats.

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Substituting

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