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wel
3 years ago
14

What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 c

m from the other) is 413 V?
Physics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

   = 413V / 0.0795 m

    = 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

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So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would tha
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3 years ago
A capacitor in a single-loop RC circuit is charged to 85% of its final potential difference in 2.4 s. What is the time constant
atroni [7]

Answer:

The  time constant is  \tau  = 1.265 s

Explanation:

From the question we are told that

     the time take to charge is  t = 2.4 \  s

The mathematically representation for voltage potential of a capacitor at different time is

        V  =  V_o  - e^{-\frac{t}{\tau} }

Where  \tau  is the time constant  

           V_o is the potential of the capacitor when it is full

     So  the capacitor potential will be  100%  when it is full thus  V_o  =100%  =  1  

and from the  question we are told that the  at the given time the potential of the capacitor is 85% = 0.85 of its final potential so

      V  = 0.85

Hence

     0.85 =  1 -  e^{-\frac{2.4}{\tau } }

       - {\frac{2.4}{\tau } }  =  ln0.15

        \tau  = 1.265 s

     

7 0
2 years ago
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