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1 year ago

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A 63.3 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 35.7 kg boy stands at one end of the board.

He walks from one end of the board to the other end with a velocity of 1.47 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?

1 answer:

Vlada [557]1 year ago

8 0

The velocity of the board relative to the ice is zero, since both are at rest.

<h3>What is relative velocity?</h3>

Relative velocity is the velocity of an object in relation to another reference object or point.

When two objects are travelling or moving with the same velocity in the same direction, the relative velocity one relative to the other is zero.

Also, when two objects are at rest, the relative velocity one relative to the other is zero.

Therefore, the velocity of the board relative to the ice is zero, since both are at rest.

Learn more about relative velocity at: brainly.com/question/24337516

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A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is

Lana71 [14]

Answer:

a

$m = 0.169 \ kg$

b

$|v_{max} |= 0.5653 \ m/s$

Explanation:

From the question we are told that

The spring constant is $k = 14 \ N/m$

The maximum extension of the spring is $A = 6.0 \ cm = 0.06 \ m$

The number of oscillation is $n = 30$

The time taken is $t = 20 \ s$

Generally the the angular speed of this oscillations is mathematically represented as

$w = \frac{2 \pi}{T}$

where T is the period which is mathematically represented as

$T = \frac{t}{n}$

substituting values

$T = \frac{20}{30 }$

$T = 0.667 \ s$

Thus

$w = \frac{2 * 3.142 }{ 0.667}$

$w = 9.421 \ rad/s$

this angular speed can also be represented mathematically as

$w = \sqrt{\frac{k}{m} }$

=> $m =\frac{k }{w^2}$

substituting values

$m =\frac{ 15 }{(9.421)^2}$

$m = 0.169 \ kg$

In SHM (simple harmonic motion )the equation for velocity is mathematically represented as

$v = - Awsin (wt)$

The velocity is maximum when $wt = \(90^o) \ or \ 1.5708\ rad$

$v_{max} = - A* w$

=> $|v_{max} |= A* w$

=> $|v_{max} |= 0.06 * 9.421$

=> $|v_{max} |= 0.5653 \ m/s$

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3 years ago

X/4 = 7 x = what is x

NISA [10]

Answer:

28

Explanation:

4 0

2 years ago

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FIGURE 2 shows a constant force, F of magnitude 20N pulled a light cord wrapped around a pulley to lift a bucket of mass 1.53kg.

slava [35]

(a) $14.3 rad/s^2$

The angular acceleration of the pulley can be found by using the equivalent of Newton's second law for rotational motions:

$\tau = I \alpha$ (1)

where

$\tau$ is the net torque on the pulley

$I=0.385 kg m^2$ is the moment of inertia of the pulley

$\alpha$ is the angular acceleration

First, we need to find the net torque. The torque exerted by the force F (forward) is:

$\tau_t = F r = (20 N)(0.330 m)=6.6 Nm$

While the frictional torque (backward) is $\tau_f = 1.1 Nm$ . So, the net torque is

$\tau = \tau_t - \tau_f=6.6 - 1.1 = 5.5 Nm$

Now, re-arranging eq.(1), we find the angular acceleration:

$\alpha = \frac{\tau}{I}=\frac{5.5}{0.385}=14.3 rad/s^2$

(b) $4.72 m/s^2$

Assuming that the string holding the bucket is inextensible, the bucket should have the same linear acceleration of a point on the edge of the pulley, which is given by

$a= \alpha r$

where

$\alpha=14.3 rad/s^2$ is the angular acceleration

r = 0.330 m is the radius of the pulley (the distance of a point at the edge from the centre)

Substituting into the equation, we find

$a=(14.3)(0.330)=4.72 m/s^2$

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2 years ago

A relief plane flying horizontally at 65.0 m/s is delivering a

SVETLANKA909090 [29]

The height of the plane delivering a food package to people stranded on an island is 722.2 m.

<h3>Time of motion of the food package</h3>

The time taken for the food package to hit the ground level is calculated as follows;

X = vt

where;

X is horizontal distance traveled by the food package
v is horizontal distance
t is time of motion

t = X/v

t = 789/65

t = 12.14 seconds

<h3>Height of the plane</h3>

h = ¹/₂gt²

where;

h is height of fall of the food package which is height of the plane
t is time of motion of food package
g is acceleration due to gravity

h = (0.5)(9.8)(12.14²)

h = 722.2 m

Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.

Learn more about height here: brainly.com/question/1739912

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1 year ago

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zloy xaker [14]

Answer:

THY ANSWER IS G..

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Explanation:

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2 years ago

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