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Lady bird [3.3K]
3 years ago
13

Explain if the efficiency of a machine can ever be greater than 100%?

Chemistry
2 answers:
Zarrin [17]3 years ago
7 0
No because a 100% efficiency means the machine is working at its best.
Marizza181 [45]3 years ago
3 0
You should download Socratic with a good app!
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jok3333 [9.3K]

Answer:

hey dude need dou

Explanation:

im top global chou in ml

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Why does potassium chloride crystallises out of solution?
kompoz [17]

Answer:

R kelly math convinced me that macaroni noodles tastes like butt

Explanation:

R kelly - way of thinking

12 = 16

13 = 18

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3 years ago
Bodies at _____ tend to remain at rest.
Klio2033 [76]

Answer:

C.

Explanation:

Newton's 3rd law of motion: Inertia. It states that bodies at rest tend to stay at rest.

8 0
2 years ago
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Os This question is about elements from these families alkali metals, alkaline earth metals (Group
Lyrx [107]

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* is a soft,silvery metal that reacts violently with water

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2 years ago
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A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
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