Answer:
1.30 mol P
Explanation:
take what is given to you (40.4g). now divide it by the molar mass of the asked element (phosphorus = 30.97g/mol)
40.4g P / 30.97g/mol P = 1.30 mol P
hope this helps :)
Respuesta:
199.5 g
Explicación:
Paso 1: Escribir la reacción balanceada
2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂
Paso 2: Calcular la masa pura de 50 g de Al
Aluminio tiene 10% de impurezas, es decir, 10% de 50 g = 5 g. Luego, tiene 50 g - 5 g = 45 g de Al puro.
Paso 3: Calcular la masa teórica de Al₂(SO₄)₃ obtenida a partir de 45 g de Al
La relación de masas de Al₂(SO₄)₃ a Al es 342:54.
45 g Al × 342 g Al₂(SO₄)₃/54 g Al = 285 g Al₂(SO₄)₃
Paso 4: Calcular la masa real de Al₂(SO₄)₃ obtenida
El rendimiento de la reacción es de 70%.
285 g × 70% = 199.5 g
Explanation:
molarity=no. of moles of solute/solution in litres
6.17M=no. of moles of solute/9.4 L
6.17×9.4=no. of moles of solute
57.9 =no. of moles of potassium fluoride KF
no. of moles=given mass /molar mass
57.9=given mass/58
3358.2 g
type the question please. The picture is to hard to see
0.05M is the concentration of the solution.
The amount of a chemical substance in a mixture is expressed by the substance's concentration. Concentration can be expressed in numerous ways. In chemistry, the terms "solvent" and "solute" are used to denote the substance of interest and the medium in which it is dissolved, respectively
Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V. To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.
C = m / V
C = 10 / 200
C = 0.05M.
Learn more about concentration here:
brainly.com/question/10725862
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