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Rufina [12.5K]
3 years ago
10

The Density equation is:

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer:

p=m/v

p equals density M equals mass and v = volume

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Draw the structures of the following compounds from their names: Pentane 3-methyl-hexane 2,4-dimethylpentane
Monica [59]

I am assuming that the compounds given are Pentane, 3-methyl-hexane, and 2, 4-dimethylpentane considering that the compounds were not separated by a comma.

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Pentane is in the form of a straight chain alkane. This is important as there are many isomers of Pentane, taking different shapes. By it's name it consists of 5 carbon atoms, and the number of hydrogen atoms should be 12, as the compound is nonpolar.

3-methylhexane is an alkane present in a hexane structure at position 3. There are thus 3 molecules at 3 ends of a hexane structure - H3C, CH3, and CH3

2,4-dimethylpentane is an alkane with respect to the formula [(H3C)2CH]2CH2.

With that information, refer to the three attachments below, for each compound given. They are in order -

8 0
3 years ago
What is the expected freezing point of a 0.50 m solution of na2so4 in water kf for water is 1.86°c/m?
Anna007 [38]

Colligative properties calculations are used for this type of problem. Calculations are as follows:<span>


ΔT(freezing point)  = (Kf)m
ΔT(freezing point)  = 1.86 °C kg / mol (0.50 mol/kg)
ΔT(freezing point)  = 0.93 °C
Tf - T = 0.93 °C
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4 0
3 years ago
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3 0
3 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
SSSSS [86.1K]

Answer:

There will remain 11.47 grams of Al(OH)3

Explanation:

Step 1: Data given

Mass of sulfuric acid = 35.0 grams

Molar mass sulfuric acid = 98.08 g/mol

Mass of aluminium hydroxide = 30.0 grams

Molar mass of aluminium hydroxide = 78.0 g/mol

Step 2: The balanced equation

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles Al(OH)3 = 30.0 grams / 78.0 g/mol

Moles Al(OH)3 = 0.385 moles

Moles H2SO4 = 35.0 grams / 98.08 g/mol

Moles H2SO4 = 0.357 moles

Step 4: Calculate the limiting reactant

For 2 moles Al(OH)3 we need 3 moles H2SO4 to produce 1 mol Al(SO4)3 and 6 moles H20

H2SO4 is the limiting reactant. It will completely be consumed ( 0.357 moles). Al(OH)3 is in excess. There will be react 2/3 * 0.357 = 0.238 moles

There will remain 0.385 - 0.238 = 0.147 moles

Mass of Al(OH)3 remaining = 0.147 moles* 78.0 g/mol = 11.47 grams

There will remain 11.47 grams of Al(OH)3

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3 years ago
Which term best describes a protein that speeds up chemical reactions in living things?
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An enzyme speeds up chemical reactions as it acts as a catalyst. 
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