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3 years ago

If you add 1 proton to Carbon, it will no longer be Carbon, it will be ________________.

Physics

1 answer:

Whitepunk [10]3 years ago

4 0

Nitrogen

Explanation:

Adding one proton to a carbon atom makes Nitrogen.

A quick introspection on atoms:

An atom is made up of three fundamental particles.
They are protons, neutrons and electrons.
The protons are positively charged and the neutrons do not carry any charges.
Electrons are negatively charged.

The difference between an atom and another is the number of protons in them. This is the atomic number.

The periodic table of element is a list of elements arranged based on the number of protons they have. Every element on the table has unique number of protons which makes it differ from another.

Atoms do not readily lose their protons because they are held by nuclear forces in the nucleus of an atom.

When an element gains a proton, it becomes another element.

Carbon has proton number of 6

If a proton is added to it, it becomes 7

This is the proton or atomic number of nitrogen.

Learn more:

Atomic number brainly.com/question/5425825

#learnwithBrainly

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It takes 20s for 3x10^6 electrons to flow through a wire ,what is the current?

Elina [12.6K]

Answer:

Explanation:

The variables we know and are given are:

time, t = 20s

Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)

We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:

I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)

If we substitute these values, we will get I as:

I = Q / t

I = 3x10^-6 / 20

I = 1.5x10^-7 A

Hope this helps!

6 0

3 years ago

Two forces of magnitude 8N and 4N act at right angle to each other. The angle between the resultant and the 8N force is?

Marta_Voda [28]

Answer:

Draw the vector triangle (head to tail)

Let 8 be adjacent and 4 the opposite side

tan theta = 4 / 8 = .5

theta = 26.6 deg

4 0

2 years ago

The first antiparticle, the positron or antielectron, was discovered in 1932. It had been predicted by Paul Dirac in 1928, thoug

Taya2010 [7]

Answer:

Energy of Photon = 4.091 MeV

Explanation:

From the conservation of energy principle, we know that total energy of the system must remain conserved. So, the energy or particles before collision must be equal to the energy of photons after collision.

K.E OF electron + Rest Energy of electron + K.E of positron + Rest Energy of positron = 2(Energy of Photon)

where,

K.E OF electron = 3.58 MeV

Rest Energy of electron = 0.511 MeV

Rest Energy of positron = 0.511 MeV

K.E OF positron = 3.58 MeV

Energy of Photon = ?

Therefore,

3.58 MeV + 0.511 MeV + 3.58 MeV + 0.511 MeV = 2(Energy of Photon)

Energy of Photon = 8.182 MeV/2

Energy of Photon = 4.091 MeV

8 0

2 years ago

A typical oil control ring consists of _______ separate part(s).

azamat

A. three

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5 0

2 years ago

Read 2 more answers

Now let’s apply the work–energy theorem to a more complex, multistep problem. In a pile driver, a steel hammerhead with mass 200

andrew11 [14]

Answer:

a) v = 7.67

b) n = 81562 N

Explanation:

Given:-

- The mass of hammer-head, m = 200 kg

- The height at from which hammer head drops, s12 = 3.00 m

- The amount of distance the I-beam is hammered, s23 = 7.40 cm

- The resistive force by contact of hammer-head and I-beam, F = 60.0 N

Find:-

(a) the speed of the hammerhead just as it hits the I-beam and

(b) the average force the hammerhead exerts on the I-beam.

Solution:-

- We will consider the hammer head as our system and apply the conservation of energy principle because during the journey of hammer-head up till just before it hits the I-beam there are no external forces acting on the system:

ΔK.E = ΔP.E

K_2 - K_1 = P_1- P_2

Where, K_2: Kinetic energy of hammer head as it hits the I-beam

K_1: Initial kinetic energy of hammer head ( = 0 ) ... rest

P_2: Gravitational potential energy of hammer head as it hits the I-beam. (Datum = 0)

P_1: Initial gravitational potential energy of hammer head

- The expression simplifies to:

K_2 = P_1

Where, 0.5*m*v2^2 = m*g*s12

v2 = √(2*g*s12) = √(2*9.81*3)

v2 = 7.67 m/s

- For the complete journey we see that there are fictitious force due to contact between hammer-head and I-beam the system is no longer conserved. All the kinetic energy is used to drive the I-beam down by distance s23. We will apply work energy principle on the system:

Wnet = ( P_3 - P_1 ) + W_friction

Wnet = m*g*s13 + F*s23

n*s23 = m*g*s13 + F*s23

Where, n: average force the hammerhead exerts on the I-beam.

s13 = s12 + s23

Hence,

n = m*g*( s12/s23 + 1) + F

n = 200*9.81*(3/0.074 + 1) + 60

n = 81562 N

6 0

3 years ago