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wolverine [178]
2 years ago
7

In the molecule XeF2 the xenon uses which type of hybrid? O spºd O spºd? Osp? O sp3 Osp

Chemistry
1 answer:
ollegr [7]2 years ago
6 0

Answer:

sp^3d

Explanation:

The hybridization of the any molecule can be calculated by the formula \frac{number\ of\ valence\ electron\ of\ central\ atom+number\ of\ monovalent\ atom\ -chare\ with\ sign}{2}

We know that Xe have 8 valence electron and 2 monovalent atom  (F) are attached with Xe and there is no charge

So hybridization =\frac{8+2-0}{2}=5

So the hybridization will be sp^3d

Note -

2 for sp

3 for sp^2

4 for sp^3

5 for  sp^3d

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Important of organic chemistry in nursing​
sasho [114]

Answer:

Nurses must use organic chemistry to determine how the bodies of their patients metabolized glucose, and how the body reacts to it.

8 0
2 years ago
Given the balanced equation, 2 H2 + O2 -> 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent as it is present more than the required amount.

8 0
3 years ago
Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.
il63 [147K]

Answer is: the ratio of the effusion rate is 1.59 : 1.

1) rate of effusion of carbon monoxide gas = 1/√M(CO).  

rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.  

2) rate of effusion of chlorine = 1/√M(Cl₂).  

rate of effusion of chlorine = 1/√70.9.  

rate of effusion of chlorine = 0.119.  

rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

4 0
2 years ago
During which change of state do atoms lose energy
alexgriva [62]

Answer: Atoms lose energy as a gas changes to a solid.

Explanation:

6 0
2 years ago
Read 2 more answers
The ionization constant of lactic acid ch3ch(oh) co2h am acid found in the blood after strenuous exercise is 1.36×10^-4 If 20.0g
lana66690 [7]

Answer:

Explanation:

CH₃CHOHCOOH    ⇄    CH₃CHOHCOO⁻   +    H⁺

ionisation constant = 1.36 x 10⁻⁴ .

molecular weight of lactic acid = 90 g

moles of acid used = 20 / 90

= .2222

it is dissolved in one litre so molar concentration of lactic acid formed

C = .2222M

Let n be the fraction of moles ionised  

CH₃CHOHCOOH    ⇄    CH₃CHOHCOO⁻   +    H⁺

C  - nC                                          nC                  nC

By definition of ionisation constant Ka

Ka = nC x nC / C - nC

= n²C ( neglecting n in the denominator )

n² x .2222 = 1.36 x 10⁻⁴

n = 2.47  x 10⁻²

nC = 2.47  x 10⁻² x .2222

= 5.5 x 10⁻³

So concentration of hydrogen or hydronium ion = 5.5  x 10⁻³ g ion per litre .

6 0
2 years ago
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