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noname [10]
3 years ago
7

How does temperature relate to density? A- As temperature increases density increases. B- As temperature decreases density decre

ases. C- As temperature decreases density increases. D- Temperature does not change density.
Chemistry
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

The answer is c

Explanation:

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Is beeswax a mineral, a rock or neither
Tju [1.3M]

Answer:

Pretty sure its a mineral

Explanation:

Beeswax is a naturally occurring wax secreted mainly by honeybees A. mellifera, for constructing honey combs (Tulloch, 1970a). Unhydrolyzed beeswax consists of approximately 71% esters, 15% hydrocarbons, 8% free fatty acids, and 6% other components (Tulloch, 1970b).

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3 years ago
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In the periodic table, how are elements in the same group related to each other? A. They have the same atomic mass. B. They have
Irina-Kira [14]
Elements in the same group tend to have very similar properties (D). This is due to the number of valence electrons each group has.
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3 years ago
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I need yall help with this one and i can make yall brilientist if u get it right plus yall get 50 points
mixas84 [53]

Answer:

D

Explanation:

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3 years ago
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Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.
Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) <u>Trypsin</u>

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) <u>Chymotrypsin</u>

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the <u>"Lis"</u> and <u>"Arg"</u> (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the <u>"Phe"</u> (See figure 2). The second amino acid that can be broken is <u>tyrosine</u>, but this amino acid is placed in the <u>C terminal spot</u>, therefore will not be involved in the <u>hydrolysis</u>.

3 0
3 years ago
A 36.2 g object has a heat capacity of 12.5 J/ oC. How much energy (in J) is required to raise the temperature by 5.73 oC?
iren2701 [21]

Answer:

\Delta H=2592.825\ J

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of object = 36.2 g

Specific heat = 12.5 J/g°C

\Delta T=5.73\ ^0C

So,  

\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J

\Delta H=2592.825\ J

7 0
3 years ago
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