In a scientific notation, you have to put a decimal right after the first number (unless it is a zero). How many times you move the decimal from its original spot determines the answer. If you move the decimal
forward that means you put a
negative number
<span>
0.00000123 = 1.23 (moved the decimal point
forward 6 times, so the answer is --->)
</span>
<span>
</span>
Answer:
Use the simple interest formula: A = P(1 + rt) where P is the Principal amount of money to be invested at an Interest Rate R% per period for t Number of Time Periods.
First, converting R percent to r a decimal
r = R/100 = 5.5%/100 = 0.055 per year.
Solving our equation:
A = 30000(1 + (0.055 × 7)) = 41550
A = $41,550.00
The total amount accrued, principal plus interest, from simple interest on a principal of $30,000.00 at a rate of 5.5% per year for 7 years is $41,550.00.
Step-by-step explanation:
Answer: -3
Solution:
Let n be that number.
So,
Three less than 3*no = 3 more than 5*no
3*n-3=5*n+3
5n-3n=-3-3
2n=-6
n=-3
Answer:
<em>one</em><em> </em><em>solution</em><em> </em>
<em>no</em><em> </em><em>solution</em><em> </em>
<em>infinity</em><em> </em><em>solutions</em><em> </em>
Step-by-step explanation:
A: If the graphs of the equations intersect, then there is one solution that is true for both equations.
B; If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.
C; If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations
Answer:
The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 45 - 1 = 44
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12.1 - 0.4 = 11.7 units
The upper end of the interval is the sample mean added to M. So it is 12.1 + 0.4 = 12.5 units
The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.
