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Black_prince [1.1K]
3 years ago
13

Write the standard form equation of a circle with a CENTER of (11, 21) and a RADIUS of 13.

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

see screenshot

general formula is

r² = (x - x-center)² + (y - y-center)²

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Please help me with this question, image attached.
hichkok12 [17]

Answer:

corresponding angles

Step-by-step explanation:

<4 and <8 are corresponding angles

Corresponding angles are in matching corners on parallel lines

4 0
3 years ago
Read 2 more answers
two runners start 30kilometer apart and run toward each other. they meet after 3hours. One Runner runs 2 kilometers per hour fas
belka [17]

Let the slower runners speed be X kilometers per hour.

Then the faster runners speed would be X+2 kilometers per hour.


The formula for distance is Speed times time.

The distance is given as 30 kilometers and time is given as 3 hours.


Since there are two runners you need to add the both of them together.

The equation becomes 30 = 3x + 3(x+2)

Now solve for x:

30 = 3x + 3(x+2)

Simplify:

30 = 3x + 3x +6

30 = 6x + 6

Subtract 6 from each side:

24 = 6x

Divide both sides by 6:

x = 24/6

x = 4


The slower runner ran at 4 kilometers per hour.

The faster runner ran at 4+2 = 6 kilometers per hour.


3 0
3 years ago
Which of the following is a composite number between 30 and 50? A. 37 B. 33 C. 41 D. 43
Nonamiya [84]
It is answer B I hope I helped u
7 0
3 years ago
Read 2 more answers
Tyrone has a piece of yarn that is 3 feet long. he measures it again to find the number of inches. will the number of feet or th
alukav5142 [94]
3 ft is equal to 36 inches, so they are the same length
7 0
3 years ago
What are 3 consecutive integers whose product is -120
iren2701 [21]
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero

x+6=0
x=-6

x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6



use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1

the numbers are -4,-5,-6
5 0
3 years ago
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