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PolarNik [594]
3 years ago
12

I NEED HELP ASAP!!!!!!!

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Answer:

put (-3) in place of x then it will be 9-6 then f(-3)=3

DIA [1.3K]3 years ago
3 0

Answer:

f(-3)= 15

Step-by-step explanation:

f(-3) means x is equal to -3

-3 squared - 2(-3)

-3*-3 -2(-3)

*Negative multiplied by a negative equals a positive

9+6= 15

f(-3)= 15

Hope this helps!

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Probably a bit late but its A the first one ;P

Step-by-step explanation:

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A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0
3 years ago
A communications company offers a variety of calling card options. Card A has a 30¢ connection fee and then costs 2¢ per minute.
arlik [135]

Answer:

The length of the call that would cost the same with both cards is 5 minutes.

Step-by-step explanation:

Hi there!

The cost with card A can be expressed as follows:

cost A = 30 + 2 · m

Where "m" is the length of the call in minutes.

In the same way, the cost of card B will be:

cost B = 10 + 6 · m

Where "m" is the length of the call in minutes.

We have to find the value of "m" for which the call would cost the same with both cards.

Then:

cost A = cost B

30 + 2 · m = 10 + 6 · m

Subtract 10 and 2 · m to both sides of the equation:

30 - 10 =  6 · m - 2 · m

20 = 4 · m

Divide by 4 both sides of the equation:

20/4 = m

5 = m

The length of the call that would cost the same with both cards is 5 minutes.

Have a nice day!

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3 years ago
The global maxima is at what point? <br><br> A. c<br> B. b<br> C. a and b<br> D. a
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C I think but I’m not suuuper sure

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