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4 years ago

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Light of wavelength 550 nm falls on a slit that is 3.50 x 10^-3 mm wide. How far from the central . maximum will the first diffr

action maximum fringe be if the screen is 10.0 m away?

1 answer:

myrzilka [38]4 years ago

6 0

Λ $= 550 * 10^{-9}\] m.

D = 3.50*10^-6 m.$
$d = 10 m. 

m = 1

2x = ?$

Then you need to find x when n=1
or
$sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4$
≈θ for θ<<1 , so θ= $1.59x10^-4 radians$

Then you can find rhe distance of<span> bright fringe from the center:</span> $d= θD=1.59x10^-4x10m ≈ 1.6 mm$

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