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Evgen [1.6K]
3 years ago
8

Light of wavelength 550 nm falls on a slit that is 3.50 x 10^-3 mm wide. How far from the central . maximum will the first diffr

action maximum fringe be if the screen is 10.0 m away?
Physics
1 answer:
myrzilka [38]3 years ago
6 0
Λ= 550 * 10^{-9}\] m.

D = 3.50*10^-6 m.
d = 10 m. 

m = 1

2x = ?

Then you need to find x when n=1
or 
sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4
≈θ for θ<<1 , so θ=1.59x10^-4 radians

Then you can find rhe distance of<span> bright fringe from the center:</span>d= θD=1.59x10^-4x10m ≈ 1.6 mm
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