Express 9/15 as a percentage
2 answers:
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The kinetic energy of the object just after it starts its motion from the Earth surface is
where m is the object mass and
its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
and h is the maximum height reached by the object.
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
where m is the object mass and
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
Answer with Explanation:
Mass of block=1.1 kg
Th force applied on block is given by
F(x)=
Initial position of the block=x=0
Initial velocity of block=
a.We have to find the kinetic energy of the block when it passes through x=2.0 m.
Initial kinetic energy=
Work energy theorem:
Where Final kinetic energy
=Initial kinetic energy
Substitute the values then we get
Because work done=
Hence, the kinetic energy of the block as it passes thorough x=2 m=2.13 J
b.Kinetic energy =
When the kinetic energy is maximum then
Substitute x=
Substitute x=
Hence, the kinetic energy is maximum at x=
Again by work energy theorem , the maximum kinetic energy of the block between x=0 and x=2.0 m is given by
Hence, the maximum energy of the block between x=0 and x=2 m=2.48 J