We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v.
K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s
Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
Answer:
129.6 seconds
Explanation:
Given that :
α = 0.0002°c-1
θ1 = 20°C
θ2 = 5°C
Time t = one day ; Converting to seconds ; number of seconds in a day ; (24 * 60 * 60) = 86400 seconds
Let dT= change in time
Using the relation :
dT = 0.5* α * dθ * t
dθ = (20 - 5) = 15°C
dT = 0.5 * 0.0002 * 15 * 86400
dT = 129.6 seconds
Answer:
T = 2π√(L/g) = 2π√(0.80/9.8) = 1.79519... = 1.78 s is your closest option
Explanation:
4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

<h3>Further explanation</h3>
Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

<em>Q = Energy ( Joule )</em>
<em>m = Mass ( kg ) </em>
<em>c = Specific Heat Capacity ( J / kg°C ) </em>
<em>Δt = Change In Temperature ( °C )</em>
Let us now tackle the problem!

<u>Given:</u>
initial temperature of steam = t = 100.0°C
specific heat capacity of water = c = 4.186 J/gK
mass of steam = m = 18.0 gram
final temperature of water = t' = 25.0°C
specific latent heat of vaporization of water = Lv = 2268 J/g
<u>Asked:</u>
heat released = Q = ?
<u>Solution:</u>
![\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Clarge%20%7B%5Ctexttt%7Bsteam%20100%7D%5EoC%20%5Coverset%7B%5BQ_1%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%20100%7D%5EoC%20%5Coverset%7B%5BQ_2%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%2025%7D%5EoC%7D%7D)







<h3>Learn more</h3>

<h3>Answer details </h3>
Grade: College
Subject: Physics
Chapter: Thermal Physics

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water
Answer:
5.67 x 10^ 1
Explanation:
Move the decimal once to the left