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3 years ago

The units used for mass were?

Physics

1 answer:

PSYCHO15rus [73]3 years ago

5 0

Answer:

Mass in science, is measured in the metric system using units such as kilogram (about 2.2 pounds)n which are a thousand grams, grams, centigrams (hundredths of grams), and milligrams (thousandths of grams). Mass is different from weight, Weight is a force.

Explanation:

hope that helps

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Which is the property of mattter in which substance can transfer heat to electricity

vodomira [7]

<u>Conductivity</u> is the property of matter in which a substance can transfer heat or electricity.

<h3><u>Additional</u><u> </u><u>information:-</u><u> </u></h3>

Matter : Anything which occupies space and has mass is called matter.

<u>Chemical classifications</u>

Pure Substances ( made of one kind of substance )

Impure Substances ( mixture )

<u>Physical</u><u> </u><u>classifications</u><u> </u>

Solid

Liquid

Plasma ( made of ions and free electrons )

BEC ( Bose Einstein Condensate )

Fermionic Condensate ( It discovered in 2003 )

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3 years ago

A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5

harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

$E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\$

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

$P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\$

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0

3 years ago

Speed is a vector quantity. Do you agree? Justify your answer.

abruzzese [7]

Answer:

Explanation:

because speed is the rate of change in the distance travelled by an object

so, speed is scalar quantity.

<h2>Mark me as brainlist</h2>

8 0

3 years ago

Read 2 more answers

Calculate the average velocity of the cart for each fan speed. Round your answers to the nearest tenth.

serg [7]

<h2>Answer:</h2>

Answers in the explanation

<h2>Explanation:</h2>

The term speed is used to denote distance traveled divided by time. This can be expressed in a mathematical language as follows:

$v=\frac{d}{t} \\ \\ \\ v:speed \\ \\ d:distance \\ \\ t:time$

The cart with Low fan speed:

$v=\frac{500}{7.4} \\ \\ v=67.5675cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=67.6cm/s}$

The cart with Medium fan speed:

$v=\frac{500}{6.4} \\ \\ v=78.125cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=78.1cm/s}$

The cart with High fan speed:

$v=\frac{500}{5.5} \\ \\ v=90.9090cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=90.9cm/s}$

6 0

3 years ago

Read 2 more answers

You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo

S_A_V [24]

Answer:

A. Z = 185.87Ω

B. I = 0.16A

C. V = 1mV

D. VL = 68.8V

E. Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

$Z=\sqrt{R^2+\omega^2L^2}$ (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

$Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega$

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

$I=\frac{V}{Z}$ (2)

V: voltage amplitude = 30.0V

$I=\frac{30.0V}{185.87\Omega}=0.16A$

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

$V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV$ (3)

D. The voltage across the inductor is:

$V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V$

E. The phase difference is given by:

$\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°$

5 0

3 years ago