<span>Answer:
KE = (11/2)mω²r²,
particle B must have mass of 2m, while A has mass m.
Then the moment of inertia of the system is
I = Σ md² = m*(3r)² + 2m*r² = 11mr²
and then
KE = ½Iω² = ½ * 11mr² * ω² = 11mr²ω² / 2
So I'll proceed under that assumption.
For particle A, translational KEa = ½mv²
but v = ω*d = ω*3r, so KEa = ½m(3ωr)² = (9/2)mω²r²
For particld B, translational KEb = ½(2m)v²
but v = ω*r, so KEb = ½(2m)ω²r²
so total translational KE = (9/2 + 2/2)mω²r² = 11mω²r² / 2
which is equal to our rotational KE.</span>
Answer:
Acceleration of the car is
.
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :
![v^2-u^2=2ad](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad)
![a=\dfrac{v^2-u^2}{2d}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2d%7D)
![a=\dfrac{(34)^2-(29)^2}{2\times 110}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%2834%29%5E2-%2829%29%5E2%7D%7B2%5Ctimes%20110%7D)
![a=1.43\ m/s^2](https://tex.z-dn.net/?f=a%3D1.43%5C%20m%2Fs%5E2)
So, the acceleration of the car as it speeds up is
. Hence, this is the required solution.
The correct answer is A. Faster
Explanation:
Sound, which is composed of vibration, travels through waves. Additionally, the speed of sound waves is affected by the medium and the density of it. Indeed, the denser the medium is the higher the speed of sound is. For example, in the air, the speed of sound is around 343 meters per second while in water and similar liquids that have a higher density the speed is approximately 1500 meters per second, and this speed increases if the sound travels through a solid. This occurs because in dense substances particles are closer, and therefore waves can travel faster. Thus, in a denser medium will generally make a sound wave travel faster.
Answer:
∝ = 28.92 rad/s²
Explanation:
Applying third equation of motion to the angular motion, we have:
2∝θ = ωf² - ωi²
where,
∝ = angular acceleration = ?
θ = angular displacement = (27 rev)(2π rad/1 rev) = 169.64 rad/s
ωf = final angular velocity = 99 rad/s
ωi = initial angular velocity = 0 rad/s
Therefore,
(2)∝(169.64 rad) = (99 rad/s)² - (0 rad/s²)
∝ = (9801 rad²/s²)/(38.8 rad)
<u>∝ = 28.92 rad/s²</u>
Answer:
A conducter will allow electricity to flow through it. An insulator cannot conduct electricity.