Question

A 1000 kg car drives off of u 30m cliff of

Answer 1

The mechanical energy of the car is $1.54\cdot 10^6 J$

Explanation:

The mechanical energy of an object is equal to the sum of its gravitational potential energy (GPE) and its kinetic energy (KE):

E = GPE + KE

The GPE of the car is given by:

$GPE = mgh$

where

m = 1000 kg is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

h = 30 m is the height of the car above the ground

Substituting,

$GPE=(1000)(9.8)(30)=2.94\cdot 10^5 J$

The kinetic energy of the car is given by:

$KE=\frac{1}{2}mv^2$

where

m = 1000 kg

v = 50 m/s is the speed of the car

Substituting,

$KE=\frac{1}{2}(1000)(50)^2=1.25\cdot 10^6 J$

Therefore, the mechanical energy is

$E=GPE+KE=2.94\cdot 10^5 + 1.25\cdot 10^6 = 1.54\cdot 10^6 J$

Learn more about potential energy and kinetic energy:

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