A 1000 kg car drives off of u 30m cliff of
1 answer:
The mechanical energy of the car is
Explanation:
The mechanical energy of an object is equal to the sum of its gravitational potential energy (GPE) and its kinetic energy (KE):
E = GPE + KE
The GPE of the car is given by:
where
m = 1000 kg is the mass of the car
is the acceleration of gravity
h = 30 m is the height of the car above the ground
Substituting,
The kinetic energy of the car is given by:
where
m = 1000 kg
v = 50 m/s is the speed of the car
Substituting,
Therefore, the mechanical energy is
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The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.
<u>Explanation:</u>
As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,
So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.
The final kinetic energy is
= 7500 J
As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.
Work done = Final Kinetic energy - Initial Kinetic energy
Thus the work utilized for moving the car is
Work done = 7500 J - 0 J = 7500 J
Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.