A wooden artifact from a Chinese temple has a 14C activity of 41.0 counts per minute as compared with an activity of 58.2 counts
1 answer:
Answer:
Explanation:
The relation between activity and number of radioactive atom in the sample is as follows
dN / dt = λ N where λ is disintegration constant and N is number of radioactive atoms
For the beginning period
dN₀ / dt = λ N₀
58.2 = λ N₀
similarly
41 = λ N
dividing
58.2 / 41 = N₀ / N
N = N₀ x .70446
formula of radioactive decay
- λ t = ln .70446 = - .35
t = .35 / λ
λ = .693 / half life
= .693 / 5715
= .00012126
t = .35 / .00012126
= 2886.36
= 2900 years ( rounding it in two significant figures )
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The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:
- Capacitance is C = 1.8 10⁻⁶ F
A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.
Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.
In the case of resonance, the impedance term completes the circuit as a resistive system.
Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.
Angular velocity and frequency are related.
w = 2π f
Let's substitute.
Let's calculate.
C = 1.8 10⁻⁶ F
In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:
- Capacitance is C = 1.8 10⁻⁶ F
Learn more about serial RLC circuits here: brainly.com/question/15595203