Answer:
Maximum emf in the coil is 100 volt
Explanation:
We have given number of loops in the coil N = 50
Cross sectional area 
Angular speed is given 
Magnetic field is given 
We have to find the maximum emf in the coil
Maximum emf in the coil is given by 

So maximum emf induced in the coil is 100 volt
If u is about 0.2 (no unit) then the whole left side is zero.
Answer:
3
Explanation:
The half-life of a radioactive isotope is the time it takes for the mass of the sample to halve.
This can be rewritten as follows:

where
m(t) is the mass of the sample at time t
m0 is the original mass of the sample
n is the number of half-lives that passed
We see that if we take n=3, the amount of original sample left is

So 3 (3 half-lives) is the correct answer.
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω