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Xelga [282]
3 years ago
8

The temperature at which the vapor pressure of a liquid equals the environmental pressure surrounding the liquid is best defined

by which term?
Physics
2 answers:
Mila [183]3 years ago
7 0

Answer:

Boiling point

Explanation:

The temperature at which the vapor pressure of a substance equals the external atmospheric pressure is called boiling point. This phenomenon occurs under certain conditions of temperature and pressure. It varies depending on the specific properties of the substance.

Umnica [9.8K]3 years ago
5 0
<span>The temperature at which the vapor pressure of a liquid equals the environmental pressure surrounding the liquid is best defined as:

Boling Point
</span>
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7. An automobile with a radio antenna 1.0 m long travels at 100.0 km/h in a location where the Earth’s horizontal magnetic field
VashaNatasha [74]

Answer:

0.00479 volts

Explanation:

From Faraday's law of electromagnetic induction, the induced emf equals the change in magnitude flux (magnetic field strength multiplied by the area = BA) divided by the time change

Therefore we have the equation

EMF = BA÷t

Since area A = 2πr

EMF = Bπr²÷t

B = 5.5×10^(-5)

Velocity = 100km/h = 27.7778m/s

r = 1m, t = r÷V = 0.036

EMF = Bπr²÷t = (5.5×10^(-5) x π x (1)²)÷0.036 = 0.00479 Volts

3 0
3 years ago
From fastest to slowest, rank the speeds of the balls 1 s after being thrown. Rank the speeds of the balls from fastest to slowe
Rus_ich [418]

Explanation:

From the given figure,

Mass of ball A is 4.9 kg and its initial speed is 8 m/s.

Mass of ball B is 1.9 kg and its initial speed is 14 m/s.

Mass of ball C is 0.7 kg and its initial speed is 2 m/s.

We need to find the final speed of the balls 1 s after being thrown. They all are thrown upward under the action of gravity. The equation of motion is : v = u -gt, g = 10 m/s²

For ball A,

v = 8-10(1) = = -2 m/s (downward)

For B,

v = 14-10(1) = 4 m/s (upward)

For C,

v = 2-10(1) = -8 m/s (downward)

It means the ranking is B>A>C i.e. the speed of ball B is the most and that of C is least.

All the balls are moving under the action of gravity. It would mean that the acceleration for all balls is same i.e. 10 m/s²

8 0
3 years ago
Read 2 more answers
Which of the following is an example of an object that could have a net force greater than zero acting on it?
mario62 [17]
Net force is basically the force an object has when changing direction, so the answer would be D. 
5 0
3 years ago
Read 2 more answers
A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an
umka21 [38]

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

<u>Given the following data:</u>

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 m/s^2

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

Total \;mass=2 + 97

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

Force = mass \times acceleration

Substituting the given parameters into the formula, we have;

Force = 99 \times 2

Net force = 198 Newton

Read more here: brainly.com/question/24029674

3 0
2 years ago
The amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is________
maksim [4K]

Answer:

d) 2Fr

Explanation:

We know that the work done in moving the charge from the right side to the left side in the k shell is W = ∫Fdr from r = +r to -r. F = force of attraction between nucleus and electron on k shell. F = qq'/4πε₀r² where q =charge on electron in k shell  -e and q' = charge on nucleus = +e. So, F = -e × +e/4πε₀r² = -e²/4πε₀r².

We now evaluate the integral from r = +r to -r

W = ∫Fdr

= ∫(-e²/4πε₀r²)dr

= -∫e²dr/4πε₀r²

= -e²/4πε₀∫dr/r²

= -e²/4πε₀ × -[1/r] from r = +r to -r

W = e²/4πε₀[1/-r - 1/+r] = e²/4πε₀[-2/r} = -2e²/4πε₀r.

Since F = -e²/4πε₀r², Fr = = -e²/4πε₀r² × r = = -e²/4πε₀r and 2Fr = -2e²/4πε₀r.

So W = -2e²/4πε₀r = 2Fr.

So, the amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is W = 2Fr

6 0
3 years ago
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