Had to look for the options and here is my answer.
Given the situation that a poison is consumed and this prevented the acetylcholine release, the one that would most likely occur at a myoneural junction is that "sodium and potassium gates on the motor end plate will not open". Hope this helps.
Answer:
the magnetic field is leaving the sheet
Explanation:
The magnetic force is given by the expression
F = q v x B
where bold letters indicate vectors, the modulus of this expression is
F = q v B sin θ
the direction of the force is given by the right hand rule, for a positive charge
the thumb indicates the direction of the speed, in this case from right to left
the palm the direction of the force, in our case upwards
the fingers extended the direction of the magnetic field, this case after fixing the other two components it points out of the blade
In short the magnetic field is leaving the sheet
<span>V is the transition metal.
He is the noble gas.
The periodic chart is arranged with metals on the left and non-metals on the right and the noble (non-reactive) gases form the rightmost column. The transition metals are the group of elements from columns 3 through 12. Although a strict definition of transition metals is those elements that have an incomplete d sub-shell, in which case column 12 is excluded since zinc, cadmium, and mercury do have complete d sub-shells.
With that in mind, since the element V is the only element listed in the range of a transition metal, that's the answer. And since He is the only element listed in the noble gas column, that too is the answer.</span>
Answer:
ΔE = 8.77 × 10¹¹ J
Explanation:
given,
²¹⁴₈₄Po -----> ²¹⁰₈₂Pb + 42 He
Atomic masses: Pb-210 = 209.98284 amu
Po-214 = 213.99519 amu
He-4 = 4.00260 amu
1 kg = 6.022 × 10²⁶ amu;
NA = 6.022 × 10²³ mol⁻¹
c = 2.99792458 × 10⁸ m/s
energy of molecule using equation
ΔE = Δm c²
Δm is mass difference and c is speed of light
Δm = 209.98284 + 4.00260 - 213.99519
Δm = - 0.00975 amu
1 amu = 1.66 x 10⁻²⁷ kg
- 0.00975 amu = - 0.00975 x 1.66 x 10⁻²⁷ Kg
= -0.016185 x 10⁻²⁷ Kg
total mass = 6.022 × 10²³ x -0.016185 x 10⁻²⁷
= -0.097467 x 10⁻⁴ Kg
ΔE = -(0.097467 x 10⁻⁴) (3 x 10^8)²
ΔE = - 8.77 × 10¹¹
ΔE = 8.77 × 10¹¹ J
Answer:
Option d
Explanation:
From Maxwell's law, we know that;
where
E = Electric Field
B = Magnetic Field
Also from Lenz Law:
emf, e = - 
where
= magnetic flux linkage
Now, in order for the current not to be induced in the loop, option a and c do not hold.
Since from the above equations, variation in both or any of the magnetic and electric fields will result in the induction of current as both are vector.
For the option b, if we rotate the loop about the diameter or increase the size or area of the loop, it will result in the change in its magnetic flux and current will be induced as is clear from the given equation:
Now, in case of option d, if we consider a uniform magnetic field, then there won't be any variation and hence no current will be induced while we slide the wire perpendicular to the loop.
