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Anastasy [175]
3 years ago
15

A force of 45.0 n accelerates a 5.0-kg block at 5.6 m/s2 along a horizontal surface what is the coefficient of friction?

Physics
1 answer:
Sati [7]3 years ago
7 0
For 1222 = hub to lottoo for 4455774
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A passenger on your boat falls overboard. what should you do first?
yarga [219]
The very first thing that you should do when a passenger on your boat falls overboard is to throw a PFD or also known as a Personal Flotation Device. This would include anything that can help the passenger to float. But this step would differ, only if the passenger is not wearing a lifevest. 
5 0
3 years ago
Which formula correctly shows how to calculat the time taken, given the average velocity and the displacement
Alisiya [41]
We're so good here on Brainly, we can answer it
even WITHOUT seeing the choices.

     Time = (displacement) / (magnitude of average velocity) .
8 0
3 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

    gm = 1/6 ge

    gm = 1/6  9.8 m/s² = 1.63 m/s²

We calculate the range

    R = Vo² sin 2θ  / g

    R = 25² sin (2 30) / 1.63

    R= 332 m

We will calculate the time of flight,

   Y = Voy t – ½ g t2  

   Voy = Vo sin θ

When the ball reaches the end point has the same initial  height Y=0

0 = Vo sin  t – ½  g t2

0 = 25 sin (30)  t – ½ 1.63 t2

0= 12.5 t –  0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

 t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

5 0
3 years ago
Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed
ANTONII [103]

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

lifetime = 159 ns = 1.59 × 10⁻⁷ s

we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

or s = ut

so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

distance =  29.76 m

Therefore, markers are 29.76 m far apart in the laboratory

3 0
2 years ago
The total blood volume of a human is 75 ml/kg. If the volumetric flow rate is the same in adults and children, how much more blo
Tema [17]

The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

<h3>What is flow rate?:</h3>

This is the volume of fluid flowing in a vessel per unit time.

First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.

Using,

  • V = F'm................ Equation 1

Where:

  • V = Volume of the blood
  • F' = Flow rate
  • m = mass of blood.

For the Adult,

Given:

  • m = 70 kg
  • F = 75 ml/kg

Substitute these values into equation 1

  • V = 70(75)
  • V = 5250 ml.

For the child,

Given:

  • m = 20 kg
  • F = 75 ml/kg

Substitute these values into equation 1 also

  • V = 75(20)
  • V = 1500 ml.

The amount of blood that flows more through the adult than the child is

  • A = 5250-1500
  • A = 3750 ml.

Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

Learn more about flow rate here: brainly.com/question/21630019

5 0
2 years ago
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