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Ivanshal [37]
3 years ago
6

If you need to reverse the following reaction in order for it to be an intermediate reaction in a Hess's law problem, what would

be the final value for the enthalpy of reaction you use for this intermediate reaction? H2 + 0.5 O2 H2O, H = -286 kJ
Chemistry
2 answers:
Olin [163]3 years ago
4 0
When reversing a given reaction, we simply change the sign of the standard enthalpy change value. Therefore, the reaction will become:
H₂O → H₂ + 0.5O₂, ΔH = 286kJ
This is because if a certain amount of energy is released when a reaction occurs, the same amount of energy must be supplied for the reaction to occur in the reverse direction.
castortr0y [4]3 years ago
3 0

Answer:

<u>286 KJ</u> is the answer

Explanation:

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How many moles of calcium carbonate-CaCO3 = 4.15 g​
marin [14]

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

3 0
4 years ago
2. Which of the following are reactants of photosynthesis? *
natali 33 [55]

Answer:

A is the answer.

4 0
3 years ago
Read 2 more answers
What is the answer for O2 + C5H12O2 →?
ladessa [460]

Answer:

25.76

Explanation:

8 0
3 years ago
Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the secon
Karo-lina-s [1.5K]

Answer:

The right solution is:

(a) 2459.74 J/degree C

(b) 3271.769 KJ/moles

Explanation:

According to the question,

(a)

The heat capacity of the calorimeter will be:

= \frac{5682}{24.68-22.37}

= \frac{5682}{2.31}

= 2459.74 \ J/degree \ C

(b)

The change in temperature will be:

= 26.77-22.37

= 4.4 \ Degree \ C

The amount of heat released will be:

= 2459.74\times 4.4

= 10822 \ Joules

or,

= 10.822 \ KJ

Moles of benzene combusted will be:

= \frac{0.258}{78}

= 0.00330 \ Moles

hence,

The heat combustion for 1 mol of benzene will be:

= \frac{10.822}{0.00330}

= 3271.769 \ KJ/moles

6 0
3 years ago
A student places a small stone with a mass of 5 g into a graduated cylinder containing 50 mL of water. With the stone in the gra
Katen [24]

Answer:

<h2>0.20 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 75 - 50 = 25 mL

From the question we have

density =  \frac{5}{25}  =  \frac{1}{5}  = 0.2 \\

We have the final answer as

<h3>0.20 g/mL</h3>

Hope this helps you

7 0
3 years ago
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