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skelet666 [1.2K]
3 years ago
14

If an automobile air bag has a volume of 11.7 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact

Chemistry
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

33.95 grams of NaN3

Explanation:

Number of moles of NaN3 = mass (m)/MW = m/65 mole

I mole of NaN3 requires 22.4L air bag

m/65 mole of NaN3 required 11.7L

22.4m/65 = 11.7

22.4m = 65×11.7

22.4m = 760.5

m = 760.5/22.4 = 33.95grams of NaN3

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Mrrafil [7]

Answer: -

12.41 g

Explanation: -

Mass of CO₂ = 42 g

Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol

Number of moles of CO₂ = \frac{42}{44 g/mol}

= 0.9545 mol

The balanced chemical equation for this process is

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O

From the balanced chemical equation we see

12 mol of CO₂ is produced from 2 mol of C₆H₆

0.9545 mol of CO₂ is produced from \frac{2 mol C6H6 x 0.9545 mol  CO2}{12 mol CO2}

= 0.159 mol of C₆H₆

Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol

Mass of C₆H₆ =Molar mass x Number of moles

= 78 g / mol x 0.159 mol

= 12.41 g

8 0
3 years ago
A student with an unknown code of Q3A conducts a qualitative analysis of her unknown. Her results indicated the formation of a y
insens350 [35]

Answer:

Grey precipitate implies the presence of silver ions

Yellow precipitate implies the presence of lead II ions

Explanation:

Qualitative analysis provides us a quick method of identifying ions present in a sample by chemical reactions involving simple reagents. Precipitates having a unique colour is formed. The identity of ions in the sample is deduced from the colour of precipitate obtained when particular reagents are added.

In the question, a precipitate containing silver ions upon standing turn into grey colour. Similarly, lead II ions give a yellow precipitate.

6 0
3 years ago
Water and phosphorus with a total mass of 200 grams are added to a flask like the one below and then the flask is sealed with a
ohaa [14]

Answer:

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8 0
3 years ago
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

8 0
2 years ago
if a television with mass 15kg is lifted to a shelf of height 1.2m, how much gravitational potential energy is added to the tele
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