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wolverine [178]
3 years ago
5

Please help me with this question, if you can! :)

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0

Answer: The volume of the solution be if it is diluted to 10% (v/v) is 6.0 L

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of pure acid solution = 15 %

V_1 = volume of pure acid solution = 4.0 L

C_2 = concentration of diluted acid solution= 10%

V_2 = volume of diluted acid solution= ?

Putting in the values we get:

15\times 4.0=10\times V_2

V_2=6.0L

Thus the volume of the solution be if it is diluted to 10% (v/v) is 6.0 L

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Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z
Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga  →  ⁶⁷Zn  

The reaction is:

^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0
3 years ago
The half-life of a certain element is 100 days. How many half-lives will it be before only one-eighth of this element remains?
docker41 [41]

Answer:

8

Explanation:

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4 years ago
This tea kettle shows a change in the state of matter of water. Which part of the water cycle represents the same change in stat
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I think D, because water evaporates. Once it gets hot. Then condensation. I think
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Density of water is 1 g/ml. If a piece of wood with a density of 5 g/ml is
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Answer:

The piece of wood will sink

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6 0
3 years ago
Need Help ASAP
bagirrra123 [75]

a. pH=2.07

b. pH=3

c. pH=8

<h3>Further explanation</h3>

pH=-log [H⁺]

a) 0.1 M HF Ka = 7.2 x 10⁻⁴

HF= weak acid

\tt [H^+]=\sqrt{Ka.M}\\\\(H^+]=\sqrt{7.2.10^{-4}\times 0.1}\\\\(H^+]=8.5\times 10^{-3}\\\\pH=3-log~8.5=2.07

b) 1 x 10⁻³ M HNO₃

HNO₃ = strong acid

\tt pH=-log[1\times 10^{-3}]=3

c) 1 x 10⁻⁸ M HCl

\tt pH=-log[1\times 10^{-8}]=8

5 0
3 years ago
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