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aleksley [76]
3 years ago
5

If a buffer solution is 0.130 M in a weak acid (K_a = 1.7 x 10^-5) and 0.590 M in its conjugate base, what is the pH?

Chemistry
1 answer:
Serggg [28]3 years ago
8 0
Use the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.7 x 10^-5) + log(0.590/0.130) = 5.43
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The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat
user100 [1]

<u>Answer:</u> The heat required for the process is 4.24 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of benzene = 24.8 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = ?

n = number of moles = 0.318 moles

\Delta H_{rxn} = enthalpy change of the reaction  = 30.7 kJ/mol

Putting values in above equation, we get:

30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ

Hence, the heat required for the process is 4.24 kJ

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3 years ago
Am I incorrect ?<br> Or nah?
Mademuasel [1]
I think so... I'm currently learning this too but you should be correct
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Reddish brown colour
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valentina_108 [34]
Carbohydrates are classified in three major categories depending upon the number of sub units joining to form them. These are,

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The simplest single units are monosaccharides, if units are ranging between two and twenty they are called oligosaccharides and above twenty joining units they are called polysachharides.

Result:
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Connects the arteries to the veins.
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Answer:

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Explanation:

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