Answer:
<h3>Step 1: </h3>
To relate the volume and molarity of a solution at two different concentrations, the expression used is :
M₁V₁ = M₂V₂
<h3>
step 2:</h3>
(2M) V₁ = (0.15M)(250ML)
V₁ = 18.75
step 3:
<h2>Pls, branliest! :)</h2>
Answer:
I would go for number 5 . It sounds more logical to me.
Answer:
Concentration ammonium is 0.036 g/mL
Explanation:
Stock solution has concentration of 0.108g/mL. Take 10mL stock solution and add 50 mL of water meaning it has 1,08g/60mL. Ammonium sulfate has 2 molecules of cation ammonium cation. So, (1,08g/60mL.)*2=0.036 g/mL
They have 6 valance electrons.
