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kondaur
[170]
3 years ago
5
in the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MGCl (aq), how many moles of hydrogen gas will be produced from 75.0 millilite
rs of 1.0 M HCL in an access of Mg?
Chemistry
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answer:
cricket20
[7]
3 years ago
7
0
Step One
Find the moles of HCl
C = 1.0 mol/L
V = 75 mL = 75 / 1000 = 0.75 L
Note the concentration is in Liters.
<em>Formula</em>
n = C*V
<em>Solve</em>
n = 1.0 * 0.075
n = 0.075 moles
Step two
Adjust the number of moles of HCl
How every mol of H2 produced, you will require 2 mol of HCl
2/1 = 0.075/x Cross multiply
2x = 0.075 Divide by 2
x = 0.075 / 2
x = 0.0375
moles of H2 <<<<<<<<< Answer
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