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kondaur [170]
3 years ago
5

in the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MGCl (aq), how many moles of hydrogen gas will be produced from 75.0 millilite

rs of 1.0 M HCL in an access of Mg?
Chemistry
1 answer:
cricket20 [7]3 years ago
7 0
Step One
Find the moles of HCl
C = 1.0 mol/L
V = 75 mL = 75 / 1000 = 0.75 L 
Note the concentration is in Liters.

<em>Formula</em>
n = C*V 

<em>Solve</em>
n = 1.0 * 0.075 
n = 0.075 moles

Step two 
Adjust the number of moles of HCl
How every mol of H2 produced, you will require 2 mol of HCl

\frac{2 mol HCl}{1 mol H_2} =  \frac{0.075\text{mol of HCl given}}{x}

2/1 = 0.075/x  Cross multiply
2x = 0.075      Divide by 2
x = 0.075 / 2
x = 0.0375      moles of H2  <<<<<<<<< Answer
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<h3>How does the flotation process work?</h3>

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