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2 years ago

Round each number to the nearest tenth.

Mathematics

2 answers:

tatuchka [14]2 years ago

6 0

By rounding off
382.24-297.28
Becomes
382.2-297.3
=84.9

tankabanditka [31]2 years ago

5 0

382 divided by 297 equals 85 and that's a the answer rounded.

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Diane has $334 in her checking account. She writes a check for $112, makes a deposit of $100, and then writes another check for

Dmitrij [34]

Answer:

334 - 112 + 100 - 98

Step-by-step explanation:

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2 years ago

A pair of shoes cost $22.99 to make, the local store sells them for $36.99. What is the percent markup? (Round to the nearest hu

ASHA 777 [7]

C: 60.9% is the right answer

Step-by-step explanation:

The markup is calculated by using the formula

$Mark\ up=Selling\ price-make\ price$

Given

Make Price = $22.99

Selling Price = $36.99

So the mark up will be:

$Mark\ up=36.99-22.99\\=\$14$

Percent mark up will be:

$Mark\ up=\frac{Mark\ up}{Make\ price}*100\\=\frac{14}{22.99}*100\\=0.6089*100\\=60.89\%$

Rounding off to the nearest hundredth percent

60.9%

Hence,

C: 60.9% is the right answer

Keywords: Markup, Percentage

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3 years ago

“I think of a number and divide it by 5. The answer is 20.”

muminat

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Step-by-step explanation:

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2 years ago

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3 years ago

Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr

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Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

$x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}$

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

$x = \frac{-b +- R }{2*a}$

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

$x = \frac{-b +- C*i }{2*a}$

We have two complex solutions.

If D = 0

√0 = 0

then:

$x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}$

We have only one real solution (or two equal solutions, depending on how you see it)

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3 years ago