The answer is true!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The boiling point of the fluoromethane (CH3F) is higher than that of fluorine (F2).
The density of the unknown material is 0.213 ml/g
<h3>
Apparent density of the unknown material</h3>
The apparent density of the unknown material is calculated as follows;
Volume of the unknown substance = 126 ml - 102 ml = 24 ml
Density of the unknown substance = mass/volume
Density of the unknown substance = 24 ml / 112.6 g
Density of the unknown substance = 0.213 ml/g
Thus, the density of the unknown material is 0.213 ml/g
Learn more about density here; brainly.com/question/6838128
#SPJ1
Answer:
(a) H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)
(b) OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)
Explanation:
The equation for your buffer equilibrium is:
H₃PO₄(aq) + H₂O(ℓ) ⇌ H₃O⁺(aq)+ H₂PO₄⁻(aq)
(a) Adding H₃O⁺
The hydronium ions react with the basic dihydrogen phosphate ions.
H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)
(b) Adding OH⁻
The OH⁻ ions react with the more acidic hydronium ions.
OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)