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Sladkaya [172]
3 years ago
14

You plan to separate a polar and a non-polar compound using normal phase column chromatography technique. Methylene chloride (CH

2Cl2) and hexanes (C6H14)are the solvents to be used to elute the column. Which solvent should be used first
Chemistry
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

Hexane should be used first.

Explanation:

Chromatography is a method of separating the constituents of a mixture by taking advantage of their different rates of movement in a solvent over an adsorbent medium. Chromatography is a means of separation and analysis that utilises fractional separation. It is based on the principle  that if a fluid containing a number of substances is allowed to pass though an adsorbent medium, the different substances in the fluid may travel at different rates and be separated.

The rate of movement depends on the relative affinities of the constituents for the solvent and adsorbent medium. i.e solutes which are weakly adsorbed by the adsorbent medium are easily redissolved by the ascending solvent and quickly travel up the adsorbent medium. In addition to that , solutes which are very soluble in the solvent move up at a faster rate than those which  are not soluble.

In column Chromatography;

A non-polar solvent should be initiated and applied first. This is because , in a column chromatography, a non-polar compound will be removed at first then later polar compound.

Assuming a polar compound is used first, the polar compounds will be removed alongside with all the non-polar compounds.

From the two Compounds given;

We know that :

Hexane is a non-polar compound and Methylene chloride  is a polar compound. As such, Hexane should be used first.

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Calculate how much heat is absorbed by a sample that weighs 12 kilograms, has a specific heat of 0.231 kg/CJ, and is heated from
Andrei [34K]

Answer:

97 J

Explanation:

Step 1: Given data

  • Mass of the sample (m): 12 kg
  • Specific heat capacity (c): 0.231 J/kg.°C (this can also be expressed as 0.231 J/kg.K)
  • Initial temperature: 45 K
  • Final temperature: 80 K

Step 2: Calculate the temperature change

ΔT = 80 K - 45 K = 35 K

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J

4 0
3 years ago
The formation of SO3 from SO2 and O2 is an intermediate step in the manufacture of sulfuric acid, and it is also responsible for
jeka57 [31]

Answer:

118.22 atm

Explanation:

2SO₂(g) + O₂(g) ⇌ 2SO₃(g)      

KP = 0.13 = \frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}

Where p(SO₃) is the partial pressure of SO₃, p(SO₂) is the partial pressure of SO₂ and p(O₂) is the partial pressure of O₂.

  • With 2.00 mol SO₂ and 2.00 mol O₂ if there was a 100% yield of SO₃, then 2 moles of SO₃ would be produced and 1.00 mol of O₂ would remain.
  • With a 71.0% yield, there are only 2*0.71 = 1.42 mol SO₃, the moles of SO₂ that didn't react would be 2 - 1.42 = 0.58; and the moles of O₂ that didn't react would be 2 - 1.42/2 = 1.29.

The total number of moles is 1.42 + 0.58 + 1.29 = 3.29. With that value we can calculate the molar fraction (X) of each component:

  • XSO₂ = 0.58/3.29 = 0.176
  • XO₂ = 1.29/3.29 = 0.392
  • XSO₃ = 1.42/3.29 = 0.432

The partial pressure of each gas is equal to the total pressure (PT) multiplied by the molar fraction of each component.

  • p(SO₂) = 0.176 * PT
  • p(O₂) = 0.392 * PT
  • p(SO₃) = 0.432 * PT

Rewriting KP and solving for PT:

\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}=0.13\\\frac{(0.432*P_{T})^{2}}{(0.176*P_{T})^{2}(0.392*P_{T})} =0.13\\\frac{0.1866*P_{T}^{2}}{0.0121*P_{T}^{3}} =0.13\\\frac{15.369}{P_{T}}=0.13\\P_{T}=118.22 atm

5 0
3 years ago
Does anyone know how to do number 15?
vovikov84 [41]

Answer:

yes i do 980

Explanation:

i899 1/2

6 0
3 years ago
the air pressure from the atmosphere measures 0.5atm at an altitude of 18,000 ft. How much pressure is this in pounds per square
Julli [10]

14.7lb/in²

Explanation:

This is a conversion problem from atm to pounds per square inch

Pressure is the combined force per unit area of substance on another.

Given pressure = 0.5atm

To solve this problem ;

Convert from atm to N/m² to pound per square inch

    1 atm = 101325N/m²

  0.5atm = 0.5 x 101325 = 50,662.5‬N/m²

now we need to convert to pound per square inch;

     1N  = 0.225lb

     1m = 39.37in

Solving;

 101325 Nx \frac{1}{m^{2} }  x \frac{0.225lb}{1N }  x \frac{m^{2} }{39.37in x 39.37in} = 14.7lb/in²

learn more:

Pressure of gases brainly.com/question/10897667

#learnwithBrainly

8 0
3 years ago
How many electrons can be held in the second orbital
mariarad [96]
Second orbital can hold 8 electrons

3 0
3 years ago
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